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2 years ago

I’m in dyer need of the answer to this problem please help!!

Mathematics

1 answer:

ElenaW [278]2 years ago

5 0

Answer:

the x intercepts are -4 and -2

the y intercept are -2

Step-by-step explanation:

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What are the x and y intercept of c = 0.75m + 2.25?

lakkis [162]

The y intercept is 2.25 and x intercept is -3

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3 years ago

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At winds speeds above 1000 centimeters per second (cm/sec), significant sand-moving events begin to occur. Wind speeds below 100

alisha [4.7K]

Answer:

Lower limit = 1007.95 cm/s

Upper limit = 1142.05 cm/s

Step-by-step explanation:

We have to calculate a 95% CI with population's standard deviation known.

The sample is size n=60, with mean M=1075.

The confidence interval can be expressed as:

$M-z*\sigma/\sqrt{n} \leq\mu\leq M+z*\sigma/\sqrt{n}$

For a 95% CI, the value of z=1.96.

$1075-1.96*265/\sqrt{60} \leq\mu\leq 1075+1.96*265/\sqrt{60} \\\\1075-67.05 \leq\mu\leq 1075+67.05\\\\ 1007.95 \leq\mu\leq 1142.05$

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3 years ago

Can someone please help me!!!

egoroff_w [7]

The correct answer is the first one(a): To get the system B,..., the first equation multiplied by 4...

Explanation:

1. Let us first multiple the first equation in System A with 4, we would get:
4(2x - y) = 4 * 3

=> 8x - 4y = 12 --- (A)

Now add the equation (A) and the second equation of System A:

8x - 4y = 12
3x + 4y = 10
------------------
11x = 22

Hence,
System B:
2x - y = 3
11x = 22

-i

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3 years ago

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What does 10 = 4y equal to

boyakko [2]

69 ghcfhhggghjjohufdhhdjc

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2 years ago

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A continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval o

aleksklad [387]

Answer:

A continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers is a(n) __uniform__________ distribution

Step-by-step explanation:

Given that there is a continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers

Since the pdf is rectangular in shape and total probability is one we can say all values in the interval would be equally likely

Say if the interval is (a,b) P(X) = p the same for all places

Since total probability is 1,

we get integral of P(X)=p(b-a) =1

Or p= $\frac{1}{b-a}$

this is nothing but a uniform distribution continuous defined in the interval

A continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers is a(n) __uniform__________ distribution

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2 years ago