Answer:
1. y = 4x - 27
2. y = -4x - 15
Step-by-step explanation:
If two lines are parallel, then they have the same slope. So, the slope of the line we are looking for needs to be 4. We can start by writing a point-slope equation:
y - y1 = m(x - x1)
We can substitute the values we have, the point we are using is (8, 5) because it needs to be on the line:
y - 5 = 4(x - 8)
We can distribute:
y - 5 = 4x - 32
y = 4x - 27
We are not given the slope-intercept form, so we must divide both sides by two to get it:
y = 1/4 x + 8
A perpendicular line has the slope that is the negative reciprocal of the one that is given. So, the slope of the line would be - 4. We can start by writing a point-slope equation:
y - y1 = m(x - x1)
We can substitute the values we have, the point we are using is (-5, 5) because it needs to be on the line:
y - 5 = -4(x + 5)
We can distribute:
y - 5 = -4x - 20
y = -4x - 15
X² - 3x + 27 = 8x - 3 аdd 3 to both sides ⇒
+ 3 + 3
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x² - 3x + 30 = 8x subtract 8x from both sides ⇒<span>
- 8x - 8x
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x</span>² - 11x + 30 = 0 ← <span>standard form
</span>
A. Add 3 to both sides and subtract 8x from both sides.
The data is not linear. From (3, 1) to (7, 2), we add 4 to the x-value and add 1 to the y-value. This pattern continues for a little while, however, from (11, 3) to (18, 5), we add only 7 to the x-value even though we added 2 to the y-value. Given this information, we can determine that this is not linear data.
Answer:
Yes. 3x²y and -5x²y are like terms because the variables x and y have the same exponents.
