Let ∠RTS=∠RST = a (say)
∠QUA=∠QSU= b(say)
then we know , at point S, a+40+b=180. so, a+b=140 we'll use this later.
consider trianglePQR, ∠P+∠Q+∠R=180
i.e.P+(180-2b)+(180-2a)=180
P+180+180-2(a+b)=180 ⇒P+180-2(a+b)=0 ⇒P=2(140)- 180=280-180=100
hence,answer is E
Answer:
x=7
Step-by-step explanation
left part + 0.006 = right part + 0.006
----> 0.1x = 0.08x+0.14
left part -0.08x =right part - 0.08x
----> 0.02x=0.14
x=7
To solve for the last side of the triangle, use the Pythagorean Theorem:
(8)^2 + x^2 = (9)^2
x = sqrt of 17
However, this is a NEGATIVE sqrt 17 because the terminal side is in quadrant 4, meaning that this side is under the X-axis and therefore negative.
Now that you know the side opposite of u in the triangle, do opposite/hypotenuse.
sin u = -(sqrt 17)/9
Answer:
9.7 units
Step-by-step explanation:
Answer:6 minutes a lap
for 3 laps = 18
Step-by-step explanation:
12/2 = 6
6 times 3 = 18
