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nasty-shy [4]
3 years ago
12

Sunset Co. marks up merchandise 40% on cost. A DVD player costs Sunset $90. What is Sunset’s selling price? (Round your answer t

o the nearest cent.)
Mathematics
1 answer:
Whitepunk [10]3 years ago
4 0

Answer:

i think it would be 2.25 and then u would round it to the next cent

Step-by-step explanation:

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The ratio of swordfish to marlins caught on a deep sea fishing trip was 20 to 15. If 27 marlins were caught, how many swordfish
Kisachek [45]
20/15=N/27
Do cross multiplication.
20x27=540
540/15=39
So the answer ia 39.
6 0
3 years ago
What is 180% of 140?<br> A. 25.2<br><br><br> B. 128<br><br><br> C. 180<br><br><br> D. 252
Dennis_Churaev [7]

252

Therefore its D!

8 0
4 years ago
a researcher in a personal submarine begins at the surface of thr ocean. The submarine descends 20.6 meters and the ascends 5 7/
Mumz [18]

Answer:

Depth = 14.9\ metres

Step-by-step explanation:

Given

Desc = 20.6\ metres

Asc = 5\frac{7}{10}\ metres

Required

Determine the depth

The depth is the distance between the two distances as follows'

Depth = |Desc - Asc|

Substitute values

Depth = |20.6 - 5\frac{7}{10}|

Convert fraction to decimal

Depth = |20.6 - 5.70|

Depth = |14.9|

Depth = 14.9\ metres

6 0
3 years ago
The number of dollars that Lila
Marta_Voda [28]

Answer:$14

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Suppose that the probability of suffering a side effect from acertain flu vaccine is 0.005. If 1000 persons are inculated, finda
aniked [119]

Answer:

The answers to the question are

a) The probability that at most 1 person suffers side effect from the flu vaccine is 4.043×10⁻²

b) The probability that 4,5,or 6 persons suffer side effect from the flu vaccine is 0.49716.

Step-by-step explanation:

We solve the question using the formula for Poisson probability as follows

Let the probability of suffering a side effect from a certain flu vaccine be p

we have n = 1000 and p = 0.005

then by binomial theorem μ = 1000*0.005 = 5

using  Poisson probability formula, we haveP(X=k) =\frac{\lambda ^k e^{-\lambda}}{k!}

where λ = μ

for P(X=0) we have \frac{5^0e^{-5}}{0!} = 6.73×10⁻³

P(X=1) we have \frac{5^1e^{-5}}{1!} = 3.37×10⁻²

Using the addition rule, we have

P (X≤1) = P(X=0) + P(X=1) =  6.73×10⁻³ + 3.37×10⁻² = 4.043×10⁻²

b) Similarly, we have for k = 4, 5, 6 we have

P(X=4) we have \frac{5^4e^{-5}}{4!} =0.1755

P(X=5) we have \frac{5^5e^{-5}}{5!} = 0.1755

P(X=6) we have \frac{5^6e^{-5}}{6!} =0.14622

Therefore P(X=4) or P(X=5), P(X=6)  is given by

0.1755 + 0.17546 + 0.14622 = 0.49716

4 0
3 years ago
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