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AleksAgata [21]
3 years ago
15

Write the equation of the line that passes through the given point and has the given slope:

Mathematics
2 answers:
My name is Ann [436]3 years ago
8 0

Answer:

y=-x-9

Step-by-step explanation:

y-y1=m(x-x1)

y-0=-1(x-(-9))

y=-1(x+9)

y=-x-9

bekas [8.4K]3 years ago
3 0

Answer: y + x + 9 = 0

Step-by-step explanation:

equation of a line with the following values is

y - y1

-------   = -1

x - x1

enter the values of the coordinate x1 and y1 into the formula above

y - 0

-------    = -1

x - (-9)

y - 0

-------    = -1

x + 9

now cross multiply to have it in a linear form

y - 0 = -1( x + 9 )

y - 0 = -x - 9

y + x = -9

y + x + 9 =0

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Read 2 more answers
Evaluate the determinant of the matrix.<br> -4 5 6<br> 0 4 4<br> -2 -5 4<br> I need the work plz
FromTheMoon [43]

Answer:

-136

Step-by-step explanation:

We have to find the determinant of the following matrix:

\left[\begin{array}{ccc}-4&5&6\\0&4&4\\-2&-5&4\end{array}\right]

We can find the determinant by expanding via 1st column. i.e. by taking each element of 1st column and multiplying it by its co-factor matrix as shown below:

det \left[\begin{array}{ccc}-4&5&6\\0&4&4\\-2&-5&4\end{array}\right]

= (-4 \times det \left[\begin{array}{cc}4&4\\-5&4\end{array}\right]) - (0 \times (-4 \times det \left[\begin{array}{cc}5&6\\-5&4\end{array}\right]))+ ((-2) \times det\left[\begin{array}{cc}5&6\\4&4\end{array}\right])\\\\ =-4 \times (16 + 20)-(0)+(-2 \times 20-24)\\\\ =-4(36)+(-2(-4))\\\\ =-144+8\\\\ =-136

The notation det() stands for determinant of the matrix.

Therefore, the determinant of the given matrix is -136

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3 years ago
A line with a slope of the -5 passes through the points (-4, s)and (-7, 6). What is the value of s ?
Pani-rosa [81]

Answer:

Step-by-step explanation:

Set up the slope formula to solve for the unknown:

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3 years ago
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