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3 years ago

71,235.3 rounded to the nearest ten thousand.

Mathematics

1 answer:

Basile [38]3 years ago

7 0

Answer:

Step-by-step explanation:

the nearest 10 thousandth position is 7. So rounded to the nearest 10000 would by 70000.

Why?

Because the 1 is less than 5 and that does does not alter the 7 in any way.

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Add the integers. 1. -2 +(-5) 2. -2 +(-2) 3. -13 +9

Maru [420]

-7 because when it’s +(-) it’s always the same as the outside sign
-4 same thing explained above
-4

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3 years ago

Please help me!!! Will get brainliest!!!

jek_recluse [69]

The answer is B because r is negative and less than the critical value.

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4 years ago

A random sample of 100 people was taken. Eighty of the people in the sample favored Candidate A. We are interested in determinin

riadik2000 [5.3K]

Answer:

Option b - not significantly greater than 75%.

Step-by-step explanation:

A random sample of 100 people was taken i.e. n=100

Eighty of the people in the sample favored Candidate i.e. x=80

We have used single sample proportion test,

$p=\frac{x}{n}$

$p=\frac{80}{100}$

$p=0.8$

Now we define hypothesis,

Null hypothesis $H_0$ : candidate A is significantly greater than 75%.

Alternative hypothesis $H_1$ : candidate A is not significantly greater than 75%.

Level of significance $\alpha=0.05$

Applying test statistic Z -proportion,

$Z=\frac{\widehat{p}-p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}$

Where, $\widehat{p}=80\%=0.80$ and $p=75%=0.75$

Substitute the values,

$Z=\frac{0.80-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}$

$Z=\frac{0.80-0.75}{\sqrt{\frac{0.1875}{100}}}$

$Z=\frac{0.05}{0.0433}$

$Z=1.1547$

The p-value is

$P(Z>1.1547)=1-P(Z$

$P(Z>1.1547)=1-0.8789$

$P(Z>1.1547)=0.1241$

Now, the p-value is greater than the 0.05.

So we fail to reject the null hypothesis and conclude that the A is not significantly greater than 75%.

Therefore, Option b is correct.

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3 years ago

4x - y = -4 5x = 2y +1 how do I solve this using elimination?

julia-pushkina [17]

8x - 2y = -8
-5x + 2y = -1

3x = -9
x = -3

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3 years ago

Read 2 more answers

Find h. 11 in. h = [?] in in. 14 in. PLEASE OH PLEASE HELP ME IM DESPERATE

Sliva [168]

11^2 = h^2 + ( 14/2)^2

11^2 = h^2 + 7^2

121 = h^2 + 49

h^2 = 121 - 49

h^2 = 72

h = √72

4 0

3 years ago

71,235.3 rounded to the nearest ten thousand.​

71,235.3 rounded to the nearest ten thousand.