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steposvetlana [31]
3 years ago
10

Yo I’m I’m stuck on this. can I get some help pls

Mathematics
2 answers:
ikadub [295]3 years ago
7 0

Answer:

Which problem?

Step-by-step explanation:

ivanzaharov [21]3 years ago
3 0

Answer:

Which problem?

Step-by-step explanation:

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Find the smallest positive integer n such that n(n+1)(n+2) is divisible by 247.
Butoxors [25]

Answer:

37 is the smallest positive integer n such that n(n+1)(n+2) is divisible by 247.

Step-by-step explanation:

First we will find the prime factors of 247:

247 = 13 x 19 (which are both prime).

So now we need to find a number (the smallest one) that is of the form (n)(n+1)(n+2) (the product of three consecutive numbers) and that is divisible by both 13 and 19 (and therefore divisible by 247)

Let's take a look at the multiples of 13: 13, 26, 39, 52...

Let's take a look at the multiples of 19: 19, 38, 57...

We can see that the first time we have two multiples close together are the 38 (for 19) and the 39 (for 17).

So, if our number has both 38 and 39 as factors, then it will be divisible by 247.

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3 years ago
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