All categories

2 years ago

20 points free How to make a cow bark

Mathematics

1 answer:

yKpoI14uk [10]2 years ago

6 0

Answer:

RUFF RUFF RUFF RUFF RUFF

You might be interested in

What is the volume of the rectangular prism? A prism has a length of 8 inches, width of 2 inches, and height of 12 and one-half

Arte-miy333 [17]

Answer:4

Step-by-step explanation:because 4

4 0

3 years ago

Read 2 more answers

Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

<u>I will try to give as many details as possible. </u>

First of all, I just would like to say:

$\text{Use } \LaTeX !$

Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! （＊＾Ｕ＾）人（≧Ｖ≦＊）/

$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

4 0

2 years ago

A movie theater charges $9.50 for adults and $4.50 for children. For a recent showing of a movie, the theater sold 33 tickets an

choli [55]

Answer:

The number of children's tickets sold was 31 and the number of adult tickets sold was 2

Step-by-step explanation:

Let

x ---> the number of children's tickets sold

y ---> the number of adult tickets sold

we know that

the theater sold 33 tickets

$x+y=33$ -----> equation A

the theater made a total of $158.50

$4.50x+9.50y=158.50$ ----> equation B

Solve the system by graphing

Remember that the solution of the system is the intersection point both graphs

using a graphing tool

The solution is the point (31,2)

see the attached figure

therefore

The number of children's tickets sold was 31 and the number of adult tickets sold was 2

5 0

3 years ago

Find the value of k. Enter as an exact, simplified value.

Nadya [2.5K]

27.2289?=k I used sine

8 0

2 years ago

Please help me ASAP.

igomit [66]

<h3><u>Solution: </u></h3>

Radius of Cylindrical Pillar , r = 28 Cm = 0.28 m.

Height, h= 4 m.

Curved surface area of a Cylindrical = 2πrh.

Curved surface area of a pillar -

$= > \: 2 \times \frac{22}{7} \times 0.28 \times 4 = 7.04 {m}^{2}$

Curved surface area of 24 such Pillar :-

(7.04 x 24 = 168.96m²)..

Cost of painting an area of 1 m² = Rs8...

• Therefore , cost of painting 1689.6m² :-

( 168.96 x 8 = Rs 1351.68)...

3 0

2 years ago