Plsss need help now. Will give brainliest :)

Write the expression (x4)8 in simplest form.

goblinko [34]

The Answer is = 8x^4

Hope this helps! :)

8 0

3 years ago

If you could help me that would be amazing!!

earnstyle [38]

The answer is C

Please mark as a brainliest above my comment

6 0

2 years ago

Tom bought one third pickles as many pickles as alexa. Together their pickles cost 56p. How many pickles did they each buy?

nordsb [41]

Answer:

Step-by-step explanation:

let pickle bought by alexa =x

then according to given condition ,

pickle bought by Tom= (1/3) of Alexa

pickle bought by Tom= (1/3) x

hence also given

totall pickle cost = Tom cost + alexa cost = 56p

(1/3)x+x=56

taking L.C.M

(4/3)x=56

x=56*3/4

x=42 p

so it means,

<h2>Alexa cost = x = 42p</h2><h2>Tom cost = (1/3)x= (1/3)*42 = 14 p</h2>

7 0

3 years ago

A bowl contains 25 balls numbered 1 to 25. A ball is drawn and its number is noted. Without replacing the first ball, another ba

Len [333]

Well i think that if there is 25 ball there is more likely to be odd cause there is not 26 balls to make even and odds have the same amount of odd and even balls so there is one more odd than there is even

8 0

3 years ago

Read 2 more answers

Bones Brothers & Associates prepare individual tax returns. Over prior years, Bones Brothers have maintained careful records

madreJ [45]

Answer:

For this case we have the following info related to the time to prepare a return

$\mu =90 , \sigma =14$

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation would be:

$\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2$

And the best answer would be

b. 2 minutes

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

For this case we have the following info related to the time to prepare a return

$\mu =90 , \sigma =14$

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation would be:

$\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2$

And the best answer would be

b. 2 minutes

3 0

3 years ago

Plsss need help now. Will give brainliest :) ​

Plsss need help now. Will give brainliest :)