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trasher [3.6K]
3 years ago
7

suppose that you bought 500 shares of Pinewood Dairy Corporation for $39 per share several months ago. Yesterday you sold 200 of

the shares at a current price of $45 per share. How much money did you gain or lose on the shares that you sold? what was the gain of loss per share? Based on the price of $45 per share, what was the market value of ypur remaining shares yesterday?​
Mathematics
1 answer:
Orlov [11]3 years ago
6 0

Step-by-step explanation:

we bought 500 shares per $39.

so, we had to pay

500×39 = $19500

yesterday we sold 200 of the 500 shares per $45.

since the price was higher than the original buying price, we gained.

we gained 200 shares times the difference in shares price.

200×(45-39) = 200×6 = $1200

we gained $1200 in total.

we gained 45-39 = $6 per share.

we have 500-200 = 300 shares left.

the current market value of these shares is

300×45 = $13500

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M(-5,9) and N(-2,7)<br> P(-3,-7) and Q(3,-5
jek_recluse [69]

Answer:

M=(4,112)=(4,5.5) A

Step-by-step explanation:

The midpoint for two points P=(px,py) and Q=(qx,qy) is M=(px+qx2,py+qy2).

We have that px=3, py=2, qx=5, qy=9.

Thus, M=(3+52,2+92)=(4,112).

7 0
3 years ago
-6n-20=-2n+4 (1-3n)<br> how do you solve it?
Leona [35]
6n−20=−2n+4(1−3n)

Simplify both sides of the equation.

−6n−20=−2n+4(1−3n)

−6n+−20=−2n+(4)(1)+(4)(−3n)(Distribute)

−6n+−20=−2n+4+−12n

−6n−20=(−2n+−12n)+(4)(Combine Like Terms)

−6n−20=−14n+4

−6n−20=−14n+4

Add 14n to both sides.

−6n−20+14n=−14n+4+14n

8n−20=4

Add 20 to both sides.

8n−20+20=4+20

8n=24

Divide both sides by 8.

8n/8 = 24/8

n=3

7 0
3 years ago
Read 2 more answers
Here is a triangle with the height on the side of the triangle. Use the formula: (1/2)*(Base)*(Height) to find the area of the t
jasenka [17]

<em>(If one square on the graph = one centimeter)</em>

<u>b = 10cm</u>

<u>b = 10cmh = 10cm</u>

Area:

=  \frac{1}{2}  \times b \times \: h

=  \frac{1}{2 }  \times 10 \times 10

=  \frac{1}{2}  \times 100

= 50 {cm}^{2}

3 0
3 years ago
What is the range of the equation
a_sh-v [17]

The range of the equation is y>2

Explanation:

The given equation is y=2(4)^{x+3}+2

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

y=2 \cdot 4^{x+3}+2

This can be written as y=2^{1+2(x+3)}+2

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

x=2^{1+2(y+3)}+2

Solving for y, we get;

x-2=2^{1+2(y+3)}

Applying the log rule, if f(x) = g(x) then \ln (f(x))=\ln (g(x)), then, we get;

\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)

Simplifying, we get;

(1+2(y+3)) \ln (2)=\ln (x-2)

Dividing both sides by \ln (2), we have;

2 y+7=\frac{\ln (x-2)}{\ln (2)}

Subtracting 7 from both sides of the equation, we have;

2 y=\frac{\ln (x-2)}{\ln (2)}-7

Dividing both sides by 2, we get;

y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}

Let us find the positive values for logs.

Thus, we have,;

x-2>0

     x>2

The function domain is x>2

By combining the intervals, the range becomes y>2

Hence, the range of the equation is y>2

7 0
4 years ago
Pleaseee help!
user100 [1]

Step-by-step explanation:

f(3)=?

f(x)=2x+5

put x=3,

f(3)=2(3)+5=6+5=11

------------

g(2)=?

g(x)=x^2-3

put x=2,

g(2)=2^2-3=4-3=1

-----------------

g(f(-1))=?

g(x)=x^2-3

and f(-1)=2(-1)+5= -2+5=3

so g(f(-1))=3^2-3=9-3=6

----------------

f(g(-1))=?

f(x)=2x+5

g(x)=g(-1)=(-1)^2-3=1-3= -2

f(g(-1))=2(-2)+5= -4+5=1

----------------

g(f(x))=?

g(x)= x^2-3

put x=f(x),

g(f(x))=f(x)^2-3=(2x+5)^2-3=4x+25+20x-3=24x+25

7 0
4 years ago
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