Answer:
M=(4,112)=(4,5.5) A
Step-by-step explanation:
The midpoint for two points P=(px,py) and Q=(qx,qy) is M=(px+qx2,py+qy2).
We have that px=3, py=2, qx=5, qy=9.
Thus, M=(3+52,2+92)=(4,112).
6n−20=−2n+4(1−3n)
Simplify both sides of the equation.
−6n−20=−2n+4(1−3n)
−6n+−20=−2n+(4)(1)+(4)(−3n)(Distribute)
−6n+−20=−2n+4+−12n
−6n−20=(−2n+−12n)+(4)(Combine Like Terms)
−6n−20=−14n+4
−6n−20=−14n+4
Add 14n to both sides.
−6n−20+14n=−14n+4+14n
8n−20=4
Add 20 to both sides.
8n−20+20=4+20
8n=24
Divide both sides by 8.
8n/8 = 24/8
n=3
<em>(If one square on the graph = one centimeter)</em>
<u>b = 10cm</u>
<u>b = 10cmh = 10cm</u>
Area:




The range of the equation is 
Explanation:
The given equation is 
We need to determine the range of the equation.
<u>Range:</u>
The range of the function is the set of all dependent y - values for which the function is well defined.
Let us simplify the equation.
Thus, we have;

This can be written as 
Now, we shall determine the range.
Let us interchange the variables x and y.
Thus, we have;

Solving for y, we get;

Applying the log rule, if f(x) = g(x) then
, then, we get;

Simplifying, we get;

Dividing both sides by
, we have;

Subtracting 7 from both sides of the equation, we have;

Dividing both sides by 2, we get;

Let us find the positive values for logs.
Thus, we have,;


The function domain is 
By combining the intervals, the range becomes 
Hence, the range of the equation is 
Step-by-step explanation:
f(3)=?
f(x)=2x+5
put x=3,
f(3)=2(3)+5=6+5=11
------------
g(2)=?
g(x)=x^2-3
put x=2,
g(2)=2^2-3=4-3=1
-----------------
g(f(-1))=?
g(x)=x^2-3
and f(-1)=2(-1)+5= -2+5=3
so g(f(-1))=3^2-3=9-3=6
----------------
f(g(-1))=?
f(x)=2x+5
g(x)=g(-1)=(-1)^2-3=1-3= -2
f(g(-1))=2(-2)+5= -4+5=1
----------------
g(f(x))=?
g(x)= x^2-3
put x=f(x),
g(f(x))=f(x)^2-3=(2x+5)^2-3=4x+25+20x-3=24x+25