Your answer would 699.3 that is it
Sample space is (3FD , 3MD, 4MN, 6FN)
where F=female M= male N=Nurse D=doctor)
so P(doctor or female ) = (3+3+6) / 16 = 12/16 answer
Its C
(D) 4 shaded for every 2 unshaded! Hope this helps! :)
Answer:
a) If a key is selected at random, what is the probability that the key for channel 1 is pressed?
1/10
<em>There are 10 channels in total. 9 channels + 0 channel. </em>
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b) If a key is selected at random, what is the probability that the key for an even number is pressed?
5/10
0,2, 4, 6, 8 < The even numbers out of 10 channels
c) If a key is selected at random, what is the probability that the key for a number more than 6 is pressed?
3/10
<em>7, 8, 9 are the numbers greater than 6</em>
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