Answer:
In the year 2019 the number of new cars purchased will reach 15,000.
Step-by-step explanation:
t = 0 corresponds to the number of new cars purchased in 1998. If that is so, we can determine t ( time ) by making our quadratic equation here equal to 15,000 - considering that we want the year the number of cars reaches this value. t here is only the number of years to reach 15,000 cars, so we would have to add that value to 1998, to see the year that the cars will reach 15,000.
The " set up " should look like the following quadratic equation -
20t² + 135t + 3050 = 15,000 - Isolate 0 on one side,
20t² + 135t - 11950 = 0 - From here on let us solve using the quadratic equation formula,
,
... now as you can see we have two solutions, but time can't be negative, and hence our solution is the first one - about 21.3 years. 1998 + 21.3 = ( About ) The year 2019. Therefore, in the year 2019 the number of new cars purchased will reach 15,000.
Answer:
A) Neither function A nor function B has an x-intercept.
Step-by-step explanation:
Answer:
420 minutes
Step-by-step explanation:
1 hour = 60 minutes
7 * 1 hour = 7 * 60 minutes
7 hours = 420 minutes
Answer:
In 11 years
Step-by-step explanation:
To calculate the number of years it will take to depreciate to that value, we use the equation below; The amount after t years, with initial amount I at percentage of depreciation d can be represented as follows;
A = I( 1 - d)^t
In the question Using our definition, A = $8,500, I = $22,000, d = 8.5% = 8.5/100 = 0.085 and t = ?
Let’s plug these values;
8,500 = 22,000(1 - 0.085)^t
8,500 = 22,000(0.915)^t
divide both side by 22,000
8,500/22,000 = (0.915)^t
0.3864 = (0.915)^t
Taking the logarithm of both sides
log 0.3864 = log(0.915)^t
log 0.3864 = tlog 0.915
t = log 0.3864/log 0.915
t = 10.7 approximately 11 years
