Answer:
6 , 7 , 8 , 9...
Step-by-step explanation:
2x > 10
x > 5
then
x = 6 , 7 , 8, 9...
I think that I am right and also think this will helpful to you.....
Which equation is not equvilant It is c
The hours it would take to type 3.2 x 10^5 words is 1.33 x 10^2 hours.
<h3>How many hours would it take to
type 3.2 x 10^5 words?</h3>
Standard form is used in expressing large numbers in smaller numbers. It is used to transform large numbers into smaller number.
In order to write a number in standard form, the number is written as a decimal number, between 1 and 10 and multiplied by a power of 10.
For example: 1 x 10² is equivalent to 100
The first step is to determine how many words he can type in 1 hour : 40 x 60 = 2400 words = 2.4 x 10³
The second step is to divide 3.2 x 10^5 words by 2.4 x 10³
3.2 x 10^5 ÷ 2.4 x 10³ = 1.33 x 10^(5 - 3)
1.33 x 10^2 hours
To learn more about standard form, please check: brainly.com/question/25334755
#SPJ1
Answer:
9 terms
Step-by-step explanation:
Given:
1, 8, 28, 56, ..., 1
Required
Determine the number of sequence
To determine the number of sequence, we need to understand how the sequence are generated
The sequence are generated using
![\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dn%26%26r%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7Bn%21%7D%7B%28n-r%29%21r%21%7D)
Where n = 8 and r = 0,1....8
When r = 0
![\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%260%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-0%29%210%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B8%210%21%7D%20%3D%201)
When r = 1
![\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%261%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-1%29%211%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B7%211%21%7D%20%3D%20%5Cfrac%7B8%20%2A%207%21%7D%7B7%21%20%2A%201%7D%20%3D%20%5Cfrac%7B8%7D%7B1%7D%20%3D%208)
When r = 2
![\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%262%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-2%29%212%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B6%212%21%7D%20%3D%20%5Cfrac%7B8%20%2A%207%20%2A%206%21%7D%7B6%21%20%2A%202%20%2A1%7D%20%3D%20%5Cfrac%7B8%20%2A%207%7D%7B2%20%2A1%7D%20%3D2%208)
When r = 3
![\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%263%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-3%29%213%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B5%213%21%7D%20%3D%20%5Cfrac%7B8%20%2A%207%20%2A%206%20%2A%205%21%7D%7B5%21%20%2A3%2A%202%20%2A1%7D%20%3D%20%5Cfrac%7B8%20%2A%207%20%2A%206%7D%7B3%20%2A2%20%2A1%7D%20%3D%2056)
When r = 4
![\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%264%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-4%29%214%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B4%213%21%7D%20%3D%20%5Cfrac%7B8%20%2A%207%20%2A%206%20%2A%205%20%2A%204%21%7D%7B4%21%20%2A4%2A3%2A%202%20%2A1%7D%20%3D%20%5Cfrac%7B8%20%2A%207%20%2A%206%2A5%7D%7B4%2A3%20%2A2%20%2A1%7D%20%3D%2070)
When r = 5
![\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%265%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-5%29%215%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B5%213%21%7D%20%3D%20%5Cfrac%7B8%20%2A%207%20%2A%206%20%2A%205%21%7D%7B5%21%20%2A3%2A%202%20%2A1%7D%20%3D%20%5Cfrac%7B8%20%2A%207%20%2A%206%7D%7B3%20%2A2%20%2A1%7D%20%3D%2056)
When r = 6
![\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%266%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-6%29%216%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B6%212%21%7D%20%3D%20%5Cfrac%7B8%20%2A%207%20%2A%206%21%7D%7B6%21%20%2A%202%20%2A1%7D%20%3D%20%5Cfrac%7B8%20%2A%207%7D%7B2%20%2A1%7D%20%3D%2028)
When r = 7
![\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%267%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-7%29%217%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B7%211%21%7D%20%3D%20%5Cfrac%7B8%20%2A%207%21%7D%7B7%21%20%2A%201%7D%20%3D%20%5Cfrac%7B8%7D%7B1%7D%20%3D%208)
When r = 8
![\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%268%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-8%29%218%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B8%210%21%7D%20%3D%201)
The full sequence is: 1,8,28,56,70,56,28,8,1
And the number of terms is 9
Answer:
Sum angle of triangle BHD = 180°
36 + 39 + BHD = 180
BHD = 180 - 36 - 39
= 105°
BHD + x° = 180° (straight angle)
105° + x° = 180°
x = 180 - 105
= 75°
