It's hard to type and hard to read the "inverse tangent" function, as you've seen (above).
So, use "arctan x" instead.
Then the problem becomes: "differentiate cos (arctan x)."
You must apply first the rule for differentiating the cosine function, and next apply the rule for differentiating the arctan function:
(d/dx) cos (arctan x) = - sin (arctan x) * [1/(1+x^2)]
Since the plane starts at (0,0), you don't have to factor in anything except for the translation. The plane would be at (-.5, 3.5)
Answer: well search It up 1/10
Step-by-step explanation:
