3 years ago

Hellpppppppppp!!!!!!!! Find the first 4 terms of this sequence useing recursive definition

Mathematics

1 answer:

amid [387]3 years ago

3 0

hope this answer helps you dear...take care!

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What’s the correct answer for this?

STatiana [176]

Answer:

6.7

Step-by-step explanation:

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3 years ago

Can someone help me on problem number 8?

kramer

List the coordinates,
Coordinates are shown as (x,y)
If 2+2+7+7 is 16
You make those your side lengths
Coordinates are (9,7) (2,7) (2,5) (9,5)
they maybe slightly off because of the broken peice of paper

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3 years ago

mark earned $8 per hour plus and additional $50 in tips waiting tables on saturday. He earned $165 in all.

fomenos

Answer:

242+165=$407 because $8 per hour = $192 in 24 hours

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3 years ago

In triangle ABC, BD bisects Angle ABC and AD is similar to CD. Tell what kind of triangle ABC must be

Anestetic [448]

A right triangle. Hope this helps.

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2 years ago

Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.

alexgriva [62]

Recall that

$|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x$

There are three cases to consider:

(1) When $x+2$ , we have $|x+2|=-(x+2)$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4$

(2) When $x+2\ge0$ and $x-2$ , we get $|x+2|=x+2$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)+(x+2)=4$

(3) When $x-2\ge0$ , we have $|x+2|=x+2$ and $|x-2|=x-2$ , so

$|x-2|+|x+2|=(x-2)+(x+2)=2x$

So

$|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x$

4 0

2 years ago