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3 years ago

Given the graph of the line below, which is the equation of the line?

Mathematics

1 answer:

user100 [1]3 years ago

4 0

Answer:

Y = 2X+1

Step-by-step explanation:

The slope is 2 (y goes up by 2 for every 1 change in x).

The y intercept is 1 (the value of y when x = 0)

The standard form for a straight line is y = mx + b

y = 2x + 1

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Someone please helpppp!!no bs answers.<br> geometry

DaniilM [7]

Answer:

Line TB is congruent to line BR.

B is the midpoint of line TR.

Line TB plus line BR is equal to or congruent to line TR.

*wink face lol*

6 0

3 years ago

Kyla makes a triangular school pennant. The area of the triangle is 180 square inches. The base of the pennant is z inches long.

kykrilka [37]

We can represent the base as z and the height as 2z+6. We are going to use the formula A=1/2*b*h and solve for z
180=1/2*z*(2z+6)
360=2z^2+6z
0=2z^2+6z-360
0=2(z^2+3z-180)
0=(z+15)(z-12)
So z=-15 and 12 but it must be positive so then the base is equal to 12

When we plug this into 2z+6 we get 30 for the height
2(12)+6=30

Hope this helps

4 0

3 years ago

Principle = 30,000<br>Time = 4 years<br>Rate = 30<br>Then find the simple interest ?

Nutka1998 [239]

Answer:

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Given:}}}}}}\end{gathered}$

${\dashrightarrow \sf{Principle = Rs.30000}}$
${\dashrightarrow \sf {Time = 4 \: years}}$
$\dashrightarrow \sf{Rate = 30\%}$
$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{To Find:}}}}}}\end{gathered}$

$\dashrightarrow{\sf{Simple \: Interest }}$

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Using Formula:}}}}}}\end{gathered}$

$\dag{\underline{\boxed{\sf{ S.I = \dfrac{P \times R \times T}{100}}}}}$

Where

$\dashrightarrow{\sf{S.I = Simple \: Interest }}$
${\dashrightarrow{\sf{P = Principle }}}$
${\dashrightarrow{\sf{ R = Rate }}}$
${\dashrightarrow{\sf{T = Time}}}$

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Solution:}}}}}}\end{gathered}$

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{P \times R \times T}{100}}}}}}$

Substituting the values

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{30000 \times 30\times 4}{100}}}}}}$

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{30000 \times 120}{100}}}}}}$

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{3600000}{100}}}}}}$

${\quad {: \implies{\sf{ S.I = \bf{\cancel{\dfrac{3600000}{100}}}}}}}$

${\quad {: \implies{\sf{ S.I = \bf{Rs.36000}}}}}$

${\dag{\underline{\boxed{\sf{ S.I ={Rs.36000}}}}}}$

Henceforth,The Simple Interest is Rs.36000..

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Learn More:}}}}}}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

8 0

3 years ago

Read 2 more answers

What is the missing blank?

bekas [8.4K]

Answer:

<1 and <8 are alternate exterior angles

Step-by-step explanation:

Alternate means on the opposite side of the transversal

Exterior means outside the parallel lines

<1 and <8 are alternate exterior angles

4 0

3 years ago

Please help me how to multiply

Travka [436]

$Use:(a-b)^2=a^2-2ab+b^2\\-------------------------------\\\\(9-6i)^2=9^2-2\cdot9\cdot6i+(6i)^2=81-108i+36i^2\\\\=81-108i+36(-1)=81-108i-36=45-108i\\\\-------------------------------\\\\i=\sqrt{-1}\to i^2=1$

7 0

2 years ago

Read 2 more answers