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Art [367]
3 years ago
8

Plz help I need help plz

Mathematics
1 answer:
nirvana33 [79]3 years ago
6 0

Answer:

8 \frac{3}{4}

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How many times larger is 5 x 10^2 than 5 x 10^−2? A) 4 times Eliminate B) 50 times C) 400 times D) 10,000 times
Diano4ka-milaya [45]

Answer:

10,000 times

Step-by-step explanation:

10^2=100

100x5=500

10^-2=0.05

0.05 x 10,000=500

5 0
3 years ago
What total distance will be covered by traveling at 50 mph for 90 minutes?
Oliga [24]

Answer:

50 mph = 50 miles per 60 minutes = 50*105/60 miles in 105 minutes = 87.5 miles.

Step-by-step explanation:

At a constant speed of 60 mph, you are traveling 1 mile per minute. It will take you 50 minutes to travel 50 miles.

hope this helps

6 0
3 years ago
Greatest common factor of 63 and 84
Darya [45]

Answer:

21

Step-by-step explanation:

Factorization :

63 = 3×3×7

84 = 2×2×3×7

Greatest Common Factor of 63 and 84 is, 3×7 = 21

8 0
3 years ago
Problem 5<br> NEED HELP ASAPAPAPAPPA PLSSS
Arisa [49]

Answer:

Well, I got the answer ofy=-x+1 as -3,-7, 0,-4, -1,-5 and also the second one is 3x=y/2 the answer of the solutions is 0.5,3 ,1,6 ,1.2, 7.2

(Thats all I have sorry -____-)

Step-by-step explanation:

4 0
3 years ago
Thea has a key on her calculator marked $\textcolor{blue}{\bf\circledast}$. If an integer is displayed, pressing the $\textcolor
worty [1.4K]

Answer:

$9$

Step-by-step explanation:

Given: Thea enters a positive integer into her calculator, then squares it, then presses the $\textcolor{blue}{\bf\circledast}$ key, then squares the result, then presses the $\textcolor{blue}{\bf\circledast}$ key again such that the calculator displays final number as $243$.

To find: number that Thea originally entered

Solution:

The final number is $243$.

As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,

the number before $243$ must be $324$.

As previously the number was squared, so the number before $324$ must be $18$.

As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,

the number before $18$ must be $81$

As previously the number was squared, so the number before $81$ must be $9$.

3 0
3 years ago
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