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NNADVOKAT [17]
3 years ago
11

Find the distance between the two points (-10,3) and (0,27)​

Mathematics
1 answer:
crimeas [40]3 years ago
5 0

Answer:

26 units

Step-by-step explanation:

\boxed{distance \: between \: 2 \: points =  \sqrt{ {(x1 - x2)}^{2} +  {(y1 - y2)}^{2}  } }

Using the formula above,

distance between (-10, 3) and (0, 27)

=  \sqrt{ {( - 10 - 0)}^{2}  +  {(3 - 27)}^{2} }

=  \sqrt{ {10}^{2}  + ( - 24) {}^{2} }

=  \sqrt{100 + 576}

=  \sqrt{676}

= 26 units

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Anit [1.1K]
Given that,

\frac{1}{2}y \ \textgreater \  22

\frac{y}{2} \ \textgreater \  22

y \ \textgreater \  22*2

y \ \textgreater \  44

Hence, y is any number greater than 44.
4 0
3 years ago
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Graph the line with a slope of 2/3 that contains the point (−3,−5)
Anna007 [38]

Answer:

Step-by-step explanation:

So for the given information, it would be easiest to use slope-intercept form, which is y=mx + b, where m is the slope and b is the y-intercept.

We can plug in 2/3 for the slope, because we are given that.

y=2/3x + b.

To find the y-intercept, plug in the given point for x and y and solve for b.

-5 = 2/3 · (-3) + b

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b = -3

So now we have the complete equation of the line.

<u>y = 2/3x -3</u>

Now to graphing.

We can put the y-intercept, (0, -3), and the given point, (-3, -5) on a graph.

3 0
3 years ago
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Answer:

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a shopkeeper sold goods for rs 2400 and made a profit of 25% in the process. find his profit per cent if he had sold his goods f
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case 1,

Let the CP be ₹x,

SP = ₹2400

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Profit % = {(2400–x)/ x} × 100%

According to the question,

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So, CP = ₹1920

case 2,

SP = ₹2040

Profit = SP – CP

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profit % = 120/1920 × 100%

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Answer.

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