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hodyreva [135]
3 years ago
6

For his phone service, Chris pays a monthly fee of $23, and he pays an additional $0.06 per minute of use. The least he has been

charged in a month is $93.86.
What are the possible numbers of minutes he has used his phone in a month?
Usem for the number of minutes, and solve your inequality for m
Mathematics
1 answer:
meriva3 years ago
6 0

9514 1404 393

Answer:

  m ≥ 1181

Step-by-step explanation:

Chris's minimum charge indicates he uses his phone more than m minutes, where ...

  23 +0.06m ≥ 93.86

  0.06m ≥ 70.86

  m ≥ 1181

Chris uses his phone at least 1181 minutes per month.

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julsineya [31]

The equation of the newsletter function is C(x) = 75 + 0.25x and the function values are C(0) = 75, C(100) = 100, C(200) = 125 and  C(300) = 150

<h3 /><h3>How to determine the newsletter function?</h3>

From the question, the given parameters are

Initial charge = $75.00

Rate per copy = $0.25 per copy

The equation of the newsletter function is then calculated as

Total = Initial charge + Rate per copy x Number of copies

Let x represents the number of copies

So, we have

Total = Initial charge + Rate per copy x x

This gives

C(x) = 75 + 0.25x

<h3>The function values for x = 0, 100, 200 and 300</h3>

When x = 0, we have

C(0) = 75 + 0.25 x 0 = 75

When x = 100, we have

C(100) = 75 + 0.25 x 100 = 100

When x = 200, we have

C(200) = 75 + 0.25 x 200 = 125

When x = 300, we have

C(300) = 75 + 0.25 x 300 = 150

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brainly.com/question/4074386

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butalik [34]
C! All angles are the same
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Alice had 3 1/4 pounds of flour at the beginning of the week. At the end of the week, she had 2 3/4 pounds. How much has she use
Evgen [1.6K]

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Step-by-step explanation:

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A transversal intersects two parallel lines. The measures of a pair of alternate interior angles are 5v and 2w. The measures of
Nataly_w [17]

Answer:

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Step-by-step explanation:

we know that

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so

5v=2w -----> equation A

10w+5v=180 ----> equation B

substitute equation A in equation B and solve for w

10w+(2w)=180

12w=180

w=15°

Find the value of v

5v=2w -----> v=2w/5

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