Hello AljakeVillena!

You pull horizontally on a 50-kg crate with a force of 450 n and the friction force on the crate is 250 n. the acceleration of the crate is ?

Given,
- mass of crate = 50 kg
- Force you pull it with = 450 N
- Frictional force = 250 N
- Acceleration = ?
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Let's first find the total force/net force acting on the crate. The total force will be :-
- 450 N - 250 N = <u>2</u><u>0</u><u>0</u><u> </u><u>N.</u>
We subtracted the forces because both the forces act on opposite directions.
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Now, let's find the acceleration of the crate. To find the acceleration we must divide the net force by the mass. So,..
- Acceleration = Force/mass
- a = F/m
- a = 200/50
- <u>a = 4 m/s²</u>
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So, the acceleration of the crate is <u>4</u><u> </u><u>m/</u><u>s²</u><u>.</u>
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Hope it'll help you!
ℓu¢αzz ッ
Answer:
Option D, Yes, Devon should have evaluated f(3)
Step-by-step explanation:
f(x) = x^3 + x^2 − 10x + 8
<u>Step 1: Evaluate using F(3) NOT f(-3)</u>
f(3) = 3^3 + 3^2 - 10(3) + 8
f(3) = 27 + 9 - 30 + 8
f(3) = 14
Since the factor is (x - 3) the x value is x - 3 + 3 = 0 + 3 -> x = 3 not x = -3
Answer: Option D, Yes, Devon should have evaluated f(3)
Answer:
x = -12
Step-by-step explanation:
I am pretty sure the answer is 1 1/8 tablespoons of salt
2 x (5-2)^3
2 x (3)^3
2 x 27
54