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3 years ago

Please help ASAP!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Afina-wow [57]3 years ago

8 0

It’s A I’m pretty sureeee

marin [14]3 years ago

5 0

A. F(x)= log(x-2)+3 its answer A, I graphed it on a graphing calculator

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TRUE or FALSE: In the quarter circle, the radius is 4 cm and the diameter is 8 cm.

viktelen [127]

Answer: False.

Step-by-step explanation:

There does not exist a "quarter circle" as a circle with a radius of 4 units, the only notable circle that does exist is the unit circle, that is the circle where the radius is equal to 1, represented by the equatin x^2 + y^2 = 1

The term "quarter circle" actually does refer to a fourth part of a circle, not to a circle of radius 4.

So the statement is false

6 0

3 years ago

In two hours Holden completed 3/4 of his race how long will it take Holden to complete the entire race?

vivado [14]

Answer:

$\frac{1}{4}$ = 50 Minutes

Whole Race Time : 2 Hour and 50 Minutes

Step-by-step explanation:

so 2 Hour = $\frac{3}{4}$ Race completed

we need to find what 1/4 Race = x Hours

so 200 divided by 4 because $\frac{3}{4}$ Race is done.

we need to find how long to finish the whole race also known as $\frac{4}{4}$ .

200 divided by 4 = 50

so Holden still need 50 Minutes to finish the race.

8 0

2 years ago

Find the mean of this data set: 2, 5, 5

Rufina [12.5K]

Answer:

Mean = 4

Step-by-step explanation:

$Mean = \frac{\sum x}{n} = \frac{2 + 5+ 5}{3} = \frac{12}{3} = 4$

8 0

2 years ago

Read 2 more answers

How do you solve for sides a and b of a triangle when you know the value of c?

sasho [114]

Assuming you have some angle measures, you could use the Law of Sines to solve for the missing side lengths, which states that,
$\frac{a}{sinA}= \frac{b}{sinB}= \frac{c}{sinC}$ ,
where a, b, and c correspond to the given sides you have, and A, B, and C represent the angles you have.

In this scenario, you would have to have the values for c (which we do), and have the angle measure of C. In addition, we would also need an angle measure that is either A or B.

Hope this helps a bit!

:)

7 0

3 years ago

Which ordered pairs could be points on a line parallel to the line that contains (3, 4) and (–2, 2)? Check all that apply.

Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

As we go from (–2, 2) to (3, 4), x increases by 5 and y increases by 4. Thus, the slope of the line through (–2, 2) and (3, 4) is

m = rise / run = 4/5.

Use the slope-intercept form of the equation of a straight line:

y = mx + b becomes 4 = (4/5)(3) + b. Multiplying all three terms by 5, we eliminate the fraction: 20 = 12 + b. Thus, b = 8, and the equation of the line through (–2, 2) and (3, 4) is y = (4/5)x + 8.

A line parallel to this one would have the form y = (4/5)x + b; note that the slopes of these two lines are the same, but the y-intercept, b, would be different if the two lines do not coincide.

Unfortunately, you have not shared the ordered pairs given in this problem statement.

You could arbitrarily let b = 0. Then the parallel line has equation

y = (4/5)x; if x = 3, then y = (4/5)(3) = 12/5, and so (3, 12/5) lies on the parallel line.

3 0

2 years ago

Read 2 more answers