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nalin [4]
3 years ago
8

im confused with this please help i dont get any answers, it is about rounding, not sure why this question is confused

Mathematics
1 answer:
Shkiper50 [21]3 years ago
7 0

Step-by-step explanation:

<u>13,789:</u>

Tens: 13,790

Hundreds: 13,800

Thousands: 14,000

Ten thousands: 10,000

<u>24,173:</u>

Tens: 24,170

Hundreds: 24,200

Thousands: 24,000

Ten thousands: 20,000

<u>861,630:</u>

Tens: 861,630

Hundreds: 861,600

Thousands: 862,000

Ten thousands: 860,000

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Find the area of the figure​
uranmaximum [27]

Answer:

30 units

Step-by-step explanation:

The formula for finding the area of a triangle is 1/2b x h

So b = 12

and h = 5

1/2(12) = 6

6 x 5 = 30

I could be wrong here so

Here's a little tip:

I can tell you're using G.oogle Forms, so you can press ctrl + U and find the answers in the code

8 0
3 years ago
Consider the quadratic equation ax^2+bx+5=0,where a, b and c are rational numbers and the quadratic has two distinct zeros.
FrozenT [24]
You have shared the situation (problem), except for the directions:  What are you supposed to do here?  I can only make a educated guesses.  See below:

Note that if    <span>ax^2+bx+5=0    then it appears that c = 5 (a rational number).

Note that for simplicity's sake, we need to assume that the "two distinct zeros" are real numbers, not imaginary or complex numbers.  If this is the case, then the discriminant,    b^2 - 4(a)(c), must be positive.  Since c = 5, 

b^2 - 4(a)(5) > 0, or b^2 - 20a > 0.

Note that if the quadratic has two distinct zeros, which we'll call "d" and "e," then 

(x-d) and (x-e) are factors of ax^2 + bx + 5 = 0, and that because of this fact,

         - b plus sqrt( b^2 - 20a )
d =  ------------------------------------
                      2a

and

 </span>         - b minus sqrt( b^2 - 20a )
e =  ------------------------------------
                      2a

Some (or perhaps all) of these facts may help us find the values of "a" and "b."  Before going into that, however, I'm asking you to share the rest of the problem statement.  What, specificallyi, were you asked to do here?

7 0
3 years ago
Find the x-intercept for y = 3x^2 + 6x − 10
azamat

Answer:

x-intercepts: (-3.08, 0) and (1.08, 0)

Step-by-step explanation:

Given:

The function is given as:

y=3x^2+6x-10

In order to find the x-intercept, we need to equate the given function to 0 as x-intercept is the point where the 'y' value is 0. So,

y=0\\3x^2+6x-10=0

Now, this is a quadratic equation of the form ax^2+bx+c=0

We find the solution using the quadratic formula,

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Here, a=3,b=6,c=-10

Now, the solutions are:

x=\frac{-6\pm \sqrt{6^2-4(3)(-10)}}{2(3)}\\\\x=\frac{-6\pm \sqrt{36+120}}{6}\\\\x=\frac{-6\pm \sqrt{156}}{6}\\\\x=\frac{-6}{6}-\frac{2\sqrt{39}}{6}\ or\ x=\frac{-6}{6}+\frac{2\sqrt{39}}{6}\\\\x=-1-2.08\ or\ x=-1+2.08\\\\x=-3.08\ or\ x=1.08

Therefore, the x-intercepts are (-3.08, 0) and (1.08, 0)

5 0
3 years ago
Please answer the question shown in the attachment.
Lera25 [3.4K]

9514 1404 393

Answer:

  D.  ∠1 ≅ ∠3

Step-by-step explanation:

In order to show the lines parallel, you must show how one of the angles 1 or 4 relates to one of the angles 2 or 3. Possibilities include ...

  ∠1 +∠2 = ∠3 +∠4 = 180°

  ∠1 = ∠3

  ∠2 = ∠4

The second of the possibilities listed here matches choice D.

8 0
4 years ago
In the figure, BD¯¯¯¯¯ bisects ∠ABC .
pashok25 [27]
The bisector BD is perpendicular to the line segment AC then the angle formed in between is 90°. We can solve for DC using SOH CAH TOA theorem or Pythagorean theorem.
Since ∠BDA is 90°, we can examine that AD is equal to 2units. Proving this, we have BD^2=BD^2+AD^2.
3^2=DB^2+2^2
DB=5units
Therefore, DC=AC-AD and the answer is 2 units.

5 0
3 years ago
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