Answer:
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Step-by-step explanation:
denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier
then
P(A)= ∑ P(Bi)*P(C) with i from 1 to 3
P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125
from the theorem of Bayes
P(Cz/A)= P(Cz∩A)/P(A)
where
P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained
P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100
therefore
P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Answer:
1) take the first part of the equation and work it by multiplying (x+2) by 3
3(x+2)+x
3x +6+x
2)put the answer you got into the question you were given
3x + 6+x =2x +16
3)group the x variables and the non x variables
3x +x -2x =16 -6
4) Now work the equation you have
3x+x-2x=16-6
4x-2x=16-6
2x=16-6
2x=10
5) you divide both sides by the x variable
2x=10
2x/2 =10/2
x=5
therefore x is 5
Let's do subtraction by first starting with the ones place and then the tenths place of the subtrahend.
45-4=41; 44, 43, 42, 41
41-.5= 40.5; 40.9, 40.8, 40.7, 40.6, 40.5
45-4.5=40.5
We can check by using addition.
40.5+4.5=
44+1=
45
True
merry Christmas and a happy new year :)
Answer:
yes
Step-by-step explanation: