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Papessa [141]
2 years ago
15

Question in screen shot

Mathematics
1 answer:
dedylja [7]2 years ago
4 0
You have to multiply negative 1 outside of every expression. ex; -1 (1). Each x value now has to be turned into a negative. If i’m not wrong, I assume the y values would also be turned into a negative. Hope this helped :)
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Terry rides her bike for 40 minutes and plays basketball for an hour. How many calories does she burn..? (Per Minute).
Ivan

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12

Step-by-step explanation:

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Over the past 20 years, the average annual return for shortstop baseball gear has been 9% and the standard deviation has been 4%
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From the given statement above, the information that can be extracted from the data is the mean which is equal to 9 % , SD equal to 4%, n is equal to 20. we can also get the variance from SD. also, we can also determine the z-score of the data which is important in the distribution.
3 0
2 years ago
B/c = x/b<br> solve for (x)(c)
Anettt [7]

Answer:

Hi! The correct answer is x=b^2/c, c=b^2/x

Step-by-step explanation:

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6 0
3 years ago
The Michigan veteran population in 1990 was 14.2% and in 2000 was 12.4%.
Mandarinka [93]

Let x- intercept represents time

Let y-intercept represents population

Let 1990 represent initial year

Points are (0,14.2)(10,12.4)

slope m= \frac{y2-y1}{x2-x1}

= \frac{12.4-14.2}{10-0} =\frac{-1.8}{10} = -0.08

General linear equation

y= mx+b --------------(i)

here m is slope and b is intercept

plug the 1st point in equation

14.2= -0.018(0) + b

b=14.2

y= 0.018x + 14.2

replace y with p(t) and x with t

p(t) = -0.018t + 14.2


6 0
2 years ago
Can someone explain the process getting from:
spin [16.1K]
\rm 5=e^{3b}

The unknown b is stuck in the exponent position.
We can can fix that by using logarithms.
Log is the inverse operation of the exponential.

We'll take log of each side.
Log of what base tho?

Well, the base of our exponential is e,
so we'll take log base e of each side.

\rm log_e(5)=log_e(e^{3b})

We'll apply one of our log rules next:
\rm \log(x^y)=y\cdot\log(x)

This allows us to take the exponent out of the log,

\rm log_e(5)=(3b)log_e(e)

Another thing to remember about logs:
When the base of the log matches the inside of the log,
then the whole thing is simply 1,
\rm log_{10}(10)=1
\rm log_5(5)=1
\rm log_e(e)=1

So our equation simplifies to this,

\rm log_e(5)=(3b)\cdot1

As a final step, divide both sides by 3,

\rm \frac13log_e(5)=b

k, hope that helps!


6 0
3 years ago
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