The answer is 11/36
2/12 chance of rolling fours
because there are 2 sides containing a four on both dice combined and 12 sides in total.
Doubles mean you have to roll the same number simultaneously so let’s say we want to calculate the probability for double ones: then it’s 1/6 on the first dice for a one, and 1/6 on the second dice to land on a one as well.
I personally like to imagine a box like this:
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If you have one dice then it’s just a random segment on one of the lines. If you want the specific result from two dice then you want two specific segments which is also the 1 specific tile out of 36 (6 width times 6 height). So you multiply.
1/6 * 1/6 = 1/36 chance to roll double of ones
And 1/36 chance to roll double twos, threes, fours, fives, and sixes. But we don’t count the double fours because any four will do. So:
1/36 * 5 = 5/36
So for the probability of either doubles or containing a four is the probability of doubles of either number plus the probability of either dice being a four:
5/36 + 2/12 =
5/36 + 6/36 =
11/36
Answer:
tan T = 3/4
tan U = 4/3
Step-by-step explanation:
The tangent ratio is opposite / adjacent. The ratio will vary for each angle since the perspective of each angle will be different. For example Angle T has an adjacent side of 4 while Angle U has an adjacent side of 3. The tangent ratios for Angles U and T are listed below:
tan T = 3/4
tan U = 4/3
No, because the sum of any of the sides must be greater than all sides. 5.6 +4.0=9.6 which is less than 10.6, meaning that it is impossible to create a triangle with those lengths.
<h3>
Answer: x^2 + 6</h3>
Work Shown:
(f o g)(x) = f(g(x))
f(x) = x + 7
f( g(x) ) = g(x) + 7 ... replace every x with g(x)
f( g(x) ) = x^2-1 + 7 .... plug in g(x) = x^2-1
f( g(x) ) = x^2 + 6
(f o g)(x) = x^2 + 6
