Answer:
B but don't be surprised if it is not the answer given. It's just the best of a bunch of poor choices.
Explanation:
This is actually not an easy question to answer. It's one of those answers that has elements of "Some do and Some don't" in them.
A: is not true for painters and it is not necessarily true for C for painters.
D: photographer can pose his subjects. A painter can pose someone, but not always.
C: Answered under A.
I think the answer you are forced to choose is B, but neither one has to do it. Still life painters ( a bowl of fruit, a bouquet of flowers) and photographs pose the subjects carefully and do not want the fruit or flowers to move around.
I'd pick B, but it does not have to be the answer. I just think it is less wrong than the others.
Cryptographic system converts between plaintext and ciphertext. Cryptography is t<span>he process of making and using codes to secure transmission of information.
The c</span>ryptographic system involves encryption (the process of converting original message into a form unreadable by unauthorized individuals) and decryption (t<span>he process of converting the cipher text message back into plaintext so that it can be readily understood.)</span>
Answer:
public class TestImport{
public static void main(String[] args) {
String string1 = args[1];
String string2 = args[2];
System.out.println(string1 +" " +string2);
}
}
Explanation:
The solution here is to use string concatenation as has been used in this statement System.out.println(string1 +" " +string2);
When this code is run from the command line and passed atleast three command line arguments for index 0,1,2 respectively, the print statment will return the second string (that is index1) and the third argument(that is index2) with a space in-between the two string.
Answer:
#include <iostream>
using namespace std;
int main()
{
string s;
cin>>s; //reading string
int i,j;
bool has_dups=false;
int n= s.length();
for(i=0;i<n;i++) //to check for duplicate characters
{
for(j=0;j<n;j++)
{
if(j!=i && s[i]==s[j]) //to check if it is matched with itself
{
has_dups=true; //if true no need to check others
break;
}
}
}
cout<<has_dups;
return 0;
}
OUTPUT :
California
1
Explanation:
Above program finds if a character repeat itself in the string entered by user.
Answer:t internal firewall
Explanation:
Did this in class
