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PSYCHO15rus [73]
3 years ago
6

What is question a, b, c, d, e, and f? Thank you!

Mathematics
1 answer:
frosja888 [35]3 years ago
6 0

Step-by-step explanation:

a. f(-4)= 2

b. f(0) = 0

c. f(3) = -1.8

d. f(-5) = 0

e. f(x) = -2 => x = 2

f. f(x) = 0 => x = 0 or -5

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I need to find the surface area for this one pls help me
Alex

Step-by-step explanation:

so, you got the volume but don't know how to find the surface area ? that is strange for me. what's the problem ?

the surface of a cube or rectangular prism consists of 6 sides that split (for a rectangular prism) into 3 pairs of equal sides :

top and bottom

left and right

front and back

all we need to do is calculate the areas of these 6 rectangles and add them up. that's it.

in our case

top and bottom : 5×4 × 2 = 20×2 = 40 in²

left and right : 4×4 × 2 = 16×2 = 32 in²

front and back : 5×4 × 2 = 40 in²

so, in total, the whole surface area of the prism is

40 + 32 + 40 = 112 in²

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2 years ago
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Stolb23 [73]
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Answer:

the area of the mat = total area added minus the original area of the water color painting.

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L = 21 in + 3 in + 3 in because 3 in  is added to each side

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The mean time required to repair breakdowns of a certain copying machine is 93 minutes. The company which manufactures the machi
Sonja [21]

Answer:

t=\frac{88.8-93}{\frac{26.6}{\sqrt{73}}}=-1.349    

p_v =P(t_{(72)}  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can't concluce that the true mean is less than 93 min at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=88.8 represent the sample mean

s=26.6 represent the sample standard deviation for the sample  

n=73 sample size  

\mu_o =93 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean i lower than 93 min, the system of hypothesis would be:  

Null hypothesis:\mu \geq 93  

Alternative hypothesis:\mu < 93  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{88.8-93}{\frac{26.6}{\sqrt{73}}}=-1.349    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=73-1=72  

Since is a one side test the p value would be:  

p_v =P(t_{(72)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can't concluce that the true mean is less than 93 min at 5% of signficance.  

5 0
3 years ago
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