



For either square root to exist, you require that

. This is true for all

, since

is always non-negative. This means the domain of

as a function of

is all real numbers, or

or

.
Now, because

is non-negative, and the smallest value it can take on is 7, it follows that the minimum value for the positive square root must be

, while the maximum value of the negative root must be

. This means the range is

, or

, or
![(-\infty,-\sqrt7]\cup[\sqrt7,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C-%5Csqrt7%5D%5Ccup%5B%5Csqrt7%2C%5Cinfty%29)
.
Answer:
24f + 12g - 4
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
4(6f + 3g - 1)
<u>Step 2: Expand</u>
- [Distributive Property] Distribute 4: 4(6f) + 4(3g) + 4(-1)
- Multiply: 24f + 12g - 4
Answer:
answer is ‘see analysis’
Step-by-step explanation:
Answer:

Step-by-step explanation:
You are given the function g, for which

Find some values of this function:

You can see that ecah next value is 4 less than previous one, so these values form an arithmetic sequence and you have to find the nth term of this sequence. The nth term of arithmetic sequence is

where

So,
