<span>SAS
You've been given that AC = BC. So that's the first side or S of the proof. Then you've been given â 3 = â 4, which is the angle. And finally, CM = CM, which is the second S. So you have AC=BC, and â 3 = â 4, and finally CM = CM. So SAS can be used to prove that triangle ACM is congruent to triangle BCM.</span>
Answer:
1. −2.1−(5.9+3.7)
2. −20+(−40)+(−60)
3. associative properties
4. commutative properties
5. -43
Step-by-step explanation:
Answer:
Step-by-step explanation:
The standard equation of an ellipse centered at the point (h,k) is
where a is the distance from the center to one of the vertex. We have the relation ![c= \sqrt[]{a^2-b^2}](https://tex.z-dn.net/?f=c%3D%20%5Csqrt%5B%5D%7Ba%5E2-b%5E2%7D)
where c is the distance from one of the focus to the center.
The distance between one vertex and the center is 5. So a=5. The distance from one focue to the center is 3. Then c =3. So we have that 
so the equation is
1 inch equals 24 miles
5 • 24 = 120
120 miles apart
Answer:
D
Step-by-step explanation:
so we know that x + y is greater than or equal to 5 + 2 which is 7.
we also know that y is greater than 2.
therefore our answer cannot be A, E, or F.
now that we know that x + y is greater than or equal to 7, since y is greater than 2, x is less than 5, because 2 + 5 = 7.
that means our answer cannot be C.
the only two answers left are D and E.
if our answer was D, then we would have 3 + 6 is greater than or equal to 7.
this is true, so one of our answers is D.
if our answer was E, then we would have 2 - 5 is greater than or equal to 7.
this is untrue, so our answer is not E.
therefore our answer is D
