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3 years ago

Is there a dilation that maps shape III onto shape II? If so, what is the scale factor and is it an enlargement or a reduction?

Mathematics

2 answers:

Mama L [17]3 years ago

4 0

Answer:

Step-by-step explanation:

Vertex of Shape I : (1,1) (2,1) (2,2) (1,2) ---- (x,y)

Vertex of Shape II : (3,3) (6,3) (6,6) (3,6) ---(x',y') : (x*3 , y*3)

Vertex of Shape III : (2,2) (4,2) (4,4) (2,4) --- (x'',y'') -> (x' , y') : (x''*1.5 , y''*1.5)

Shape I dilate on to Shape II: Enlargement with scale factor of 3

dilation the Maps shape lll onto shape ll : Enlargement with scale factor of 1.5

valina [46]3 years ago

4 0

Answer:

Step-by-step explanation: sample answer

A dilation will map shape III onto shape II. The bottom left coordinate of shape III is (2, 2) and the bottom left coordinate of shape II is (3, 3). So, to get the corresponding coordinates of shape II, multiply the coordinates of shape III by 2/3 . This is true for every set of coordinates. So, the scale factor is 3/2. The scale factor is greater than 1, so the dilation is an enlargement.

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kompoz [17]

Answer:

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3 years ago

Find the value of tan30+cot30+sin60

Aliun [14]

Hello!

This is a problem about relating values of the Unit Circle.

First, we need to figure out the specific "points" of each angle measure of 30 and 60.

For the angle measure 30, the point will be $(\frac{\sqrt{3}}{2},\frac{1}{2})$ .

For the angle measure 60, the point will be $(\frac{1}{2},\frac{\sqrt{3}}{2})$ .

The tangent value of a point will be its $y$ value over its $x$ value.

$\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}=\frac{1}{2}*\frac{2}{\sqrt{3}}=\frac{1}{\sqrt{3}}=\frac{\sqrt{3}}{3}$

The cotangent value of a point will be the reciprocal of the tangent value, which we found previously.

$\frac{3}{\sqrt{3}}=\frac{3\sqrt{3}}{3}=\sqrt{3}$

The sine value of a point will be the $y$ value of the point.

$\frac{\sqrt{3}}{2}$

So the values we have so far are $\frac{\sqrt{3}}{3}+\sqrt{3}+\frac{\sqrt{3}}{2}$

Now we have to find the LCD to add these together, which in this case would be 6.

$\frac{2\sqrt{3}}{6}+\frac{6\sqrt{3}}{6}+\frac{3\sqrt{3}}{6}$

Which adds up to $\frac{11\sqrt{3}}{6}$ , which is in simplest radical form.

Hope this helps!

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malfutka [58]

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4 years ago

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Snowcat [4.5K]

Answer:

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Licemer1 [7]

x= 5

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3 years ago

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