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Dahasolnce [82]
3 years ago
8

In ABC ,AB = 7 and AC = 17. Find measure B to the nearest degree.

Mathematics
2 answers:
Gekata [30.6K]3 years ago
4 0
21 should be the right answer
Kryger [21]3 years ago
4 0

Answer:

∠B=68°

Step-by-step explanation:

We are given a right angled triangle ΔABC with ∠A=90°, AB = 7 and AC = 17.

as  ΔABC is a right angled triangle so we will use trignometric identity to find the measure of angle B.

with respect to ∠B we are given:

P=AC=17

and  B=AB=7

hence using the tangent trignometric identity we have:

\tan B=\dfrac{P}{B}=\dfrac{17}{7}=2.4286\\ \\B=\arctan 2.4286=67.62 \degree

Hence, to the nearest degree the measure of ∠B=68°


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Vanessa swims 7.25 feet below sea level. Her friend Emily swims 5.4 feet further down. How many feet did Emily swim down to?
grin007 [14]
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8 0
2 years ago
use the table to find each ratio 8 white socks and 6 black socks and 4 blue socks and 5 brown socks ... white socks to brown soc
nevsk [136]
<h3>Answer:</h3>
  • white : brown = 8 : 5
  • black : total = 6 : 23
<h3>Explanation:</h3>

Each of the ratio components (white socks, brown socks, black socks, total socks) has an associated number (8, 5, 6, 23). Write the desired ratio using the associated numbers.

8 0
3 years ago
25% of 614 is what number. Round your answer to the nearest tenth
mihalych1998 [28]

Answer:

153.5

Step-by-step explanation:

Given 25% of 614

That’s 25% /100% x 614

0.25 x 614

153.5

3 0
3 years ago
Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.5 and a mean diameter of 205
Crank

Answer:

P(205-0.3=204.7

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

Step-by-step explanation:

Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info

Where \mu=205 and \sigma=1.5

We can begin finding this probability this probability

P(205-0.3=204.7

For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}

And we can find the z scores for each limit and we got:

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

6 0
3 years ago
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