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allochka39001 [22]
3 years ago
6

Graph the hyperbola with equation quantity x plus 3 squared divided by 25 minus the quantity of y plus 5 squared divided by 4 =

1

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
7 0

Hello,

Please, see the graph in the attached file.

Thanks.

Sliva [168]3 years ago
7 0

Answer:

Step-by-step explanation:

As we know the general formula of the hyperbola is:

(x-h)²/a² - (y-k)²/b² = 1, where

  • (h,k) is the center
  • a is the semi-major axis
  • b is the semi-minor axis

In this situation, the equation is:

(x+3)²/25 - (y+5)²/4 = 1

=> the center is: (-3, -5)

a = 5

b = 2

  • As we know their slopes are +/- \frac{b}{a} so

-5 = +2/5 (-3) + b ---> b= -3.8

-5 = -2/5 (-3) + b ---> b= -6.2

Hence, you plot the equations y=2/5x -3.8  and y = -2/5 x - 6.2 by assigning values of x and plotting them against y as the attached photo.

Hope it will find you well.

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Answer:

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Step-by-step explanation:

We have these following probabilities:

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100 - 61 = 39% probability that Christine does not find a coach.

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a. What is the probability that Christine fails the course?

21% of 61%(finds a tutor) plus 51% of 39%(does not find a tutor). So

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This can be formulated by the Bayes formula:

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening given that A happened and P(A|B) is the probability of A happening given that B happened.

In this question.

P(B|A) is the probability of finding a tutor given that she failed.

P(B) is the probability of finding a tutor. So P(B) = 0.61.

P(A|B) is the probability of failing when finding a tutor. So P(A|B) = 0.21

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So

P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.61*0.21}{0.327} = 0.3917

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