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vesna_86 [32]
3 years ago
8

What solution is y = 2x + 2 y = -2x + 4 ?

Mathematics
1 answer:
brilliants [131]3 years ago
6 0

Answer:

x = \frac{1}{2} , y = 3

Step-by-step explanation:

y = 2x + 2 → (1)

y = - 2x + 4 → (2)

Substitute y = 2x + 2 into (2)

2x + 2 = - 2x + 4 ( add 2x to both sides )

4x + 2 = 4 ( subtract 2 from both sides )

4x = 2 ( divide both sides by 4 )

x = \frac{2}{4} = \frac{1}{2}

Substitute this value into (1) for value of y

y = 2(\frac{1}{2} ) + 2 = 1 + 2 = 3

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Answer:

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Step-by-step explanation:

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3 0
3 years ago
If f(x) = x-2/x+1, then f(n+1)) is equal to
Y_Kistochka [10]
Answer: f(n+1) = (n - 1)/(n + 2)

Explanation:

f(x) = (x - 2)/x+1

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f(n+1) = (n + 1 - 2)/(n + 1 + 1)
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4 0
3 years ago
Simplify this expression: -8w+(-4z)+2+6w+9z-7
White raven [17]

Answer:

-2w+5z-5

Step-by-step explanation:

-8w+(-4z)+2+6w+9z-7

Step 1: Group the terms together

-8w+6w+(-4z)+9z+2-7

Step 2: Add like terms

(-8w+6w)+(-4z+9z)+(2-7)

-2w+5z-5

Thats as simplified as it can get :)

5 0
4 years ago
What is 2x+3x-4?????<br> .
Minchanka [31]

Answer:

5x - 4

Step-by-step explanation:

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8 0
4 years ago
Read 2 more answers
Use the equation to answer the following question y=(x-3(x+2)/(x+4)(x-4)(x+2)
givi [52]

Answer:

See below

Step-by-step explanation:

The given rational function is;

y=\frac{(x-3)(x+2)}{(x+4)(x-4)(x+2)}

The given function is not continuous where the denominator is equal to zero.

(x+4)(x-4)(x+2)=0

The function is discontinuous at x=-4,x=4,x=-2

b) The point at x=-2 is a removable discontinuity(hole) because (x+2) is common to both the numerator and the denominator.

The point at x=-4 and x=4 are  non-removable discontinuities(vertical asymptotes)

c) The equation of the vertical asymptotes are x=-4 and x=4

To find the equation of the horizontal asymptote, we take limit to infinity.

\lim_{x\to \infty}\frac{(x-3)(x+2)}{(x+4)(x-4)(x+2)}=0

The horizontal asymptote is y=0

8 0
3 years ago
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