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Kaylis [27]
3 years ago
9

Emily has 7 apples . she cuts each apple into 6 slices. how many slices does Emily have ? white an equation to show how you slov

ed the problem .
Mathematics
2 answers:
Nezavi [6.7K]3 years ago
8 0

If you multiply 7 by 6 you get 42

So 7•6=42

gogolik [260]3 years ago
4 0
Your answer will be 4 2
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Keith had 694 green, yellow and blue marbles altogether. he had 3 times as many blue marbles as yellow marbles. there were 90 fe
scZoUnD [109]
Let the number of blue marbles be x

number of yellow marbles = x/3

number of green = x- 90

ATQ

x + x/3 + x - 90 = 694

2x + x/3 = 784

(6x + x)/3 = 784

7x/3 = 784

x = 784 x 3/7

x = 112 x 3

x = 336

number of blue marbles = 336
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3 years ago
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10 will be your answer
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A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the
grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = \frac{diameter}{2}=\frac{66}{2} =33 \ mm

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = \frac{4}{3}\pi r^3

Now Volume of Gumball = \frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = \frac{diameter}{2}=\frac{58}{2} =29 \ mm

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = \frac{4}{3}\pi r^3

So Volume of gumball's spherical hollow core = \frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = 150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = 48347.6\ mm^3

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

8 0
3 years ago
HELP WILL MARK YOU BRAINLIEST NO GUESSES PLZ!!!!
ozzi

x° + 90° + 52.6 = 180°

<em>because</em><em> </em><em>a</em><em> </em><em>triangle</em><em> </em><em>adds</em><em> </em><em>up</em><em> </em><em>to</em><em> </em><em>1</em><em>8</em><em>0</em><em>°</em><em> </em><em>and </em><em>that</em><em> </em><em>spec</em><em>ific</em><em> </em><em>triangle</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>right</em><em> </em><em>angle </em><em>triangle</em><em> </em><em>which</em><em> </em><em>means</em><em> </em><em>that</em><em> </em><em>it</em><em> </em><em>consist</em><em>s</em><em> </em><em>of</em><em> </em><em>angle</em><em> </em><em>adding</em><em> </em><em>up</em><em> </em><em>to</em><em> </em><em>9</em><em>0</em><em>°</em>

3 0
3 years ago
What is the standard form equation of the line shown below? Graph of a line going through negative 2, 3 and 1, negative 3
V125BC [204]

Answer:

3. 2x + y = −1

Step-by-step explanation:

To find the equation of the line, we write it first in the slope-intercept form:

y=mx+q

where

m is the slope

q is the y-intercept

From the graph, we see that the line crosses the y-axis at y = -1, so the y-intercept is -1:

q=-1

Now we have to find the slope, by calculating the rate of change of the line through 2 points:

m=\frac{y_2-y_1}{x_2-x_1}

Taking the two points at (-2,3) and (1,-3), we find:

m=\frac{-3-3}{1-(-2)}=\frac{-6}{3}=-2

So the equation of the line is

y=-2x-1

Now we have to re-arrange it in the standard form, so in the form

ax+bx=c

where a, b and c are integer numbers.

To do that, we simply add +2x on both sides of the equation of the line in the slope-intercept form, and we get:

y+2x=-1

So, option 3).

6 0
3 years ago
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