Answer:
a) D = 4.88 * 10^(-14) m^2 / s
b) <em>t </em>= 1.1 hr
Solution:
a) Magnesium in Aluminum diffusion:
D = Do * exp(-Qd / RT)
= (1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15)
= 4.88 * 10^(-14) m^2 / s
D = 4.88 * 10^(-14) m^2 / s
b) The composition remains same at say the distance Xo:
(Cx - Co) / (Cs - Co) = Constant
Xo^2 / D_{550} * <em>t </em>= Xo^2 / D_{450} * 15
D_{550} * <em>t </em>= D_{450} * 15
(1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15) * <em>t</em>
(4.88 * 10^(-14) m^2 / s) * 15
by, solving for <em>t </em>we get:
<em>t </em>= 1.1 hr
So, the time required is 1.1 hr.
Answer:
try putting a lot of rice on the screen.
Explanation:
if it got water in it that should help it.
These were later renamed to "Specialized Technology" and "Simscape Components" to help explain this difference.
Specialized Technology (Second Generation) is a Simulink based library and has been around for longer. It can still connect to Simscape, but in the same way you can connect Simulink models to Simscape -- that is, you need converters and sometimes to break algebraic loops, etc. It also has more dedicated electrical power systems capabilities. If your model will be only power systems, and especially if it's a larger model, I'd recommend this one.
Simscape Components (Third Generation) is built using the Simscape language and therefore connects directly with other Simscape blocks. If you plan to use other Simscape domains like mechanical, hydraulic, etc. I'd recommend this one.
Answer:
It wouldn't be legal practice of SLS’
Explanation:
The Internet service address is the address of the internet where we getting the address of the internet sometimes it is known as the computer address of the host machine.
Since the miller has changed the Ip address continuously in a constant manner also the other address which is giving by the internet service provider The transfer of IP address, Miller will be able to receive their network. That sort of practice is not legal of SLS.
<span>d) all of these is your correct answer</span>
