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zmey [24]
3 years ago
8

#11 i

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0

The area of a shape is the amount of space a shape can occupy, while the perimeter is the sum of its lengths.

  • <em>The perimeter is </em>18 + 3\sqrt 5 + 3\sqrt 2<em>units</em>
  • <em>The area of the sanctuary is 27 square units</em>

We have:

A = (5,7)\\B=(8, 7)\\C=(8, 1)\\D=( 1, 1)\\E=( 1, 4)\\F= ( 5,4)

<u>Perimeter</u>

See attachment for the layout of the sanctuary

BC = \sqrt{(8 - 8)^2 + (7 - 1)^2} = 6

EF = \sqrt{(1 - 5)^2 + (4 - 4)^2} = 4

FA = \sqrt{(5 - 5)^2 + (4 - 7)^2} = 3

From the attachment, the sides are

<em>AB, BF, FC, CD, DE and EA</em>

Start by calculating the length of each side using the following distance formula:

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_2)^2}

So, we have:

AB = \sqrt{(5 - 8)^2 + (7 - 7)^2} = 3

BF = \sqrt{(8 - 5)^2 + (7 -1)^2} = \sqrt{45} = 3\sqrt 5

FC = \sqrt{(8 - 5)^2 + (1 -4)^2} = \sqrt{18} = 3\sqrt 2

CD = \sqrt{(8 - 1)^2 + (1 - 1)^2} = 7

DE = \sqrt{(1 - 1)^2 + (1 - 4)^2} = 3

EA = \sqrt{(1 - 5)^2 + (4 -7)^2} = 5

So, the perimeter (P) is:

P = AB + BF + FC + CD + DE + EA

P = 3 + 3\sqrt 5 + 3\sqrt 2 + 7 + 3 + 5

P = 18 + 3\sqrt 5 + 3\sqrt 2

<em>Hence, the perimeter is </em>18 + 3\sqrt 5 + 3\sqrt 2<em>units</em>

<u />

<u>Area</u>

To calculate the area, we need to divide the sanctuary into three.

  1. <em>Triangle ABF</em>
  2. <em>Triangle EFA</em>
  3. <em>Trapezium CDEF</em>

The area of ABF is:

Area = \frac 12 \times AB \times FA

Where:

AB = 3

FA = \sqrt{(5 - 5)^2 + (4 - 7)^2} = 3

Area = \frac 12 \times 3 \times 3

Area = \frac 92

The area of EFA is:

Area = \frac 12 \times EF \times FA

Where:

FA = 3

EF = \sqrt{(1 - 5)^2 + (4 - 4)^2} = 4

So:

Area = \frac 12 \times 4 \times 3

Area = 6

The area of CDEF is:

Area = \frac 12(CD + EF) \times DE

Where

CD = 7

EF = 4

DE = 3

So, we have:

Area = \frac 12 (7 + 4) \times 3

Area = \frac 12 \times 11 \times 3

Area = \frac {33}2

So, the area of the sanctuary is:

Area = \frac 92 + 6 + \frac {33}2

Area = \frac {9 +12 + 33}2

Area = \frac {54}2

Area = 27

<em>Hence, the area of the sanctuary is 27 square units</em>

Read more about areas and perimeters at:

brainly.com/question/11957651

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Answer:

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Step-by-step explanation:

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  3. Add: 69+1
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<em>Hope this helped!! :)</em>

<em>Brainliest?!?!</em>

<em>Stay safe and have a wonderful day/afternoon/night!!!</em>

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Speedy, the human fly, is shot from a cannon whose opening is 12 feet high. After 2 elapsed seconds, Speedy is 108 feet in the a
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The graph of Speedy's height in the air with time, which is based on a

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Reasons:

The given parameters are;

The height of the cannon = 12 feet

Speedy's height after 2 seconds = 108 feet

Speedy's height after 3 seconds = 108 feet

Required: To select the best representation of the quadratic modelling Speedy's height, h(t), as a function of elapsed time, t?

Solution:

The path of Speedy's motion is a parabola

From the question, we have, that the initial height, at <em>t</em> = 0 is the height of the cannon = 12 feet

Therefore;

The equation has a constant term of 12

Given that the time it takes Speedy to rise above 108 feet and return to 108 feet = 3 - 2 = 1 second, we have;

The maximum height occurs between the 2nd and the 3rd second.

The path of a parabola is symmetric about the maximum point, therefore;

The maximum point occur at time \displaystyle 2 \, s + \frac{3 - 2}{2} \, s  = 2.5 \, s

Therefore, the x-coordinate of the vertex is t = 2.5 s

From the general equation of a parabola, a·x² + b·x + c, the x-coordinate of the vertex is; \displaystyle \mathbf{ -\frac{b}{2 \cdot a}}

From the given option, we have the option; h(t) = -16·t² + 80·t + 12, which has;

Constant = 12

Vertex = \displaystyle -\frac{80}{2 \times (-16) } = 2.5

Therefore;

The best representation of Speedy's height is; <u>h(t) = -16·t² + 80·t + 12</u>

<em>The possible question options are;</em>

<em>h(t) = 1.07·t² + 5.33·t + 101.60</em>

<em>h(t) = 16·t² + 80·t + 12</em>

<em>h(t) = -1.07·t² + 5.33·t 101.60</em>

<em>h(t) = -16·t² + 80·t + 12 </em>

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2W - 3

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