<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
5.3
Step-by-step explanation:
Cos(68) = adjacent/hypotenuse
Cos(68) = 2/AC
AC = 2/cos(68)
AC = 5.3389343253
AC = 5.3
Because there are only two things you can do with these two " family" members. 81 divided by 9 is 9. 9 times 9 is 81. Strictly speaking, there should be three in the family: 9,9 and 81 9 is the square root of 81. 81 is the 9 squared.
Answer:
first
Step-by-step explanation:
half of right angle
