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denis-greek [22]
3 years ago
8

If g(x) = 9(x - 3)2 - 6, which statement is true?

Mathematics
1 answer:
Effectus [21]3 years ago
8 0

Answer:

D?

Step-by-step explanation:

im sorry if incorrect

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ANTONII [103]
The answer is C. if you need the work I can give it to you
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Find the measures of the missing angles
rodikova [14]
2,7, and 6 are all 70 degrees. 1,4,5, and 8 are all 110 degress
7 0
4 years ago
Every day, the Webster Pet Store uses 3/10 of a bag of dog food to feed the dogs. How many days will 1 4/5 bags of dog food last
shepuryov [24]

Answer:

6 days

Step-by-step explanation:

1 + 4/5 = 5/5 + 4/5 = 9/5 = 18/10 bags of dog food

18/10 ÷ 3/10 = 18/3 = 6 days

4 0
3 years ago
Simplify:
wlad13 [49]

Answer:

The answer to your question is  letter C. 7y³  + 7n²y²  - 22y²

Step-by-step explanation:

                                   y²(4y + 7n² + 2) - 3y² (-y + 8)

Multiply

                                 4y³ + 7n²y² + 2y² + 3y³ - 24y²

Use the associative property for like terms

                               (4y³ + 3y³) + (2y² - 24y²) + 7n²y²

Simplify like terms

                                7y³ - 22y² + 7n²y²   or    7y³  + 7n²y²  - 22y²        

5 0
4 years ago
g The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control
Rudiy27

Answer:

0.1426 = 14.26% probability that at least one of the births results in a defect.

Step-by-step explanation:

For each birth, there are only two possible outcomes. Either it results in a defect, or it does not. The probability that a birth results in a defect is independent of any other birth. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC).

This means that p = \frac{1}{33}

A local hospital randomly selects five births.

This means that n = 5

What is the probability that at least one of the births results in a defect?

This is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(\frac{1}{33})^{0}.(\frac{32}{33})^{5} = 0.8574

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.8574 = 0.1426

0.1426 = 14.26% probability that at least one of the births results in a defect.

4 0
3 years ago
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