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sergiy2304 [10]
3 years ago
8

What is the first step to solving for x in the equation 9x-7=10? how would you check your solution

Mathematics
1 answer:
mihalych1998 [28]3 years ago
7 0

Answer:

<h2><em><u>In</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>equation</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>first</u></em><em><u> </u></em><em><u>step</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>add</u></em><em><u> </u></em><em><u>7</u></em><em><u> </u></em><em><u>on</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>right </u></em><em><u>hand</u></em><em><u> </u></em><em><u>side</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>isolate </u></em><em><u>the</u></em><em><u> </u></em><em><u>variable </u></em><em><u>term</u></em><em><u> </u></em><em><u>on</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>one</u></em><em><u> </u></em><em><u>side</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>equation</u></em><em><u>.</u></em><em><u> </u></em><em><u>Therefore</u></em><em><u>,</u></em></h2>

<h2><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em><u>9</u></em><em><u>x</u></em><em><u>=</u></em><em><u>1</u></em><em><u>0</u></em><em><u>+</u></em><em><u>7</u></em><em><u>=</u></em><em><u>1</u></em><em><u>7</u></em></h2>

<h2><em><u>Step</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>will </u></em><em><u>be</u></em><em><u> </u></em><em><u>dividing </u></em><em><u>both</u></em><em><u> </u></em><em><u>sides </u></em><em><u>of</u></em><em><u> </u></em><em><u>t</u></em><em><u>he</u></em><em><u> </u></em><em><u>equation </u></em><em><u>by</u></em><em><u> </u></em><em><u>9</u></em><em><u>.</u></em></h2>

<h2><em><u>x</u></em><em><u>=</u></em><em><u>1</u></em><em><u>7</u></em><em><u>/</u></em><em><u>9</u></em><em><u>.</u></em></h2>

<h2><em><u>.</u></em><em><u>•</u></em><em><u>.</u></em><em><u> </u></em><em><u>we</u></em><em><u> </u></em><em><u>got</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>value </u></em><em><u>of</u></em><em><u> </u></em><em><u>x</u></em><em><u>!</u></em></h2>

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-3x-3y=3 and y=-5x-17
Thepotemich [5.8K]
The solution is (-4,3)
-3x-3y=3
y=-5x-17
so find the y in the first equation in terms of x
-3x-3y=3
-3y=3x+3
y=-x-1
then set the two equations equal to each other
y=-x-1
y=-5x-17
-x-1=-5x-17
4x=-16
x=-4
now put the x into one of the equations
-3(-4)-3(y)=3
12-3y=3
-3y=-9
y=3
so the solution is (-4,3)
to check it, put the points into equations and see if they're correct
-3(-4)-3(3)=3
12-9=3
3=3 correct

3=-5(-4)-17
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3=3 correct
5 0
4 years ago
Please help will mark as brainless
Wewaii [24]

Answer:

1.  r =  \sqrt[3]{\frac{3v}{4\pi } }

divide v by 4/3, this is the same as multiplying v by 3/4 so you have 3v/4

then divide v by \pi so you now have 3v/4\pi

then get rid of the ^3 on r by putting the solution for r under a ∛

2. a) The equation might need to be written in terms of a because you may not know the value of a, but you know the value of everything else. If this is the case then you can simply rewrite the equation so that you can plug it all into a calculator and avoid certain possible errors.

     b)

 s = ut + 1/2 at^{2}

subtract ut from both sides: s - ut = 1/2 at^{2}

multiply both sides by 2: 2(s - ut)

divide both sides by t^{2}: \frac{2(s - ut) }{t^{2} } = a

answer: a =  \frac{2(s - ut) }{t^{2} }

I'm not entirely sure about b) for question 2 so you might wanna double check that with a friend

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3 years ago
Find the missing side lengths. leave your answers as radicals in simplest form.
Murrr4er [49]

Answer:

x = 4 , y = 2

Step-by-step explanation:

Using the sine / tangent ratios in the right triangle and the exact values

sin60° = \frac{\sqrt{3} }{2} and tan60° = \sqrt{3} , then

sin60° = \frac{opposite}{hypotenuse} = \frac{2\sqrt{3} }{x} = \frac{\sqrt{3} }{2} ( cross- multiply )

x \sqrt{3} = 4\sqrt{3} ( divide both sides by \sqrt{3} )

x = 4

and

tan60° = \frac{opposite}{adjacent} = \frac{2\sqrt{3} }{y} = \sqrt{3} ( multiply both sides by y )

y \sqrt{3} = 2\sqrt{3} ( divide both sides by \sqrt{3} )

y = 2

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