(PLEASE HELP ASAP) Marc mixes blue and yellow paint to make his favorite shade of green, which he'll use to paint his house. He
has 14 cans of blue paint and 20 cans of yellow paint when he starts. He wants the same green color every time he mixes, so the amounts of blue and yellow must always be proportional to the original mixture. On day 1, he mixes 4 cans of blue and 6 cans of yellow. On day 2, he mixes 6 cans of blue and 9 cans of yellow. Fill in the blanks to find the highest number of cans of each color Marc can mix to make the same shade of green on day 3.
2. On days 1 and 2 how much blue paint did Marc use? How much yellow paint?
3. How many cans of each type of paint does Marc have left for day 3?
4. Day 3’s mixture must use the same simplified ratio of blue to yellow as the other two days. What is the greatest number of cans of blue and yellow paint Marc can mix on day 3? Assume he mixes only whole cans of paint.
So subtract 2q from both sides. This will cancel out the 2q on the left. So the equation right now should be 10=5q. Now divide each side by 5. 10/5=2 2=q. That's the answer! Hope this helped!!
