x = 3
2x + y - z = 3 → (1)
- x + y + 2z = 0 → (2)
3x + 2y + z = 9 → (3)
we require to eliminate the y and z terms from the equations
(1) + (3) : 5x + 3y = 12 → (4)
multiply (1) by 2
4x +2y - 2z = 6 → (5)
(2) + (5) : 3x + 3y = 6 → (6)
(4) - (6) : 2x = 6 ⇒ x = 3
Answer:
B. 10
C. All real numbers.
Step-by-step explanation:
6 (2x-4) = 8(x + 2)
Distribute the numbers outside of the factors:
12x - 24 = 8x + 16
Subtract both sides by '8x'
12x - 8x - 24 = 8x - 8x + 16
4x - 24 = 16
Add '24' to both sides:
4x = 40
Divide both sides by 4:
x = 10. Therefore, <u>B. 10</u> is the correct answer.
3(4p - 2) = -6(1 - 2p)
Distribute the numbers similarly to the example before:
12p - 6 = -6 + 12p
Subtract '12p' from both sides:
12p - 12p -6 = -6 + 12p - 12p
0 -6 = -6
Add '6' to both sides:
0 - 6 + 6 = -6 + 6
0 = 0
Therefore, the solution consists of <u>all real numbers.</u>
It would be 2/10 or 1/5 simplified
What? I don't understand what you mean...
