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maxonik [38]
2 years ago
15

Domain in interval notation please

Mathematics
2 answers:
Scrat [10]2 years ago
7 0

Answer:

[-7, negitive infinity]

[-2, positive infinty]

Step-by-step explanation:

HOPE THIS HELPS!

Brainliest...

weqwewe [10]2 years ago
4 0

Answer:

[-7,-∞) U [-2,∞)

Step-by-step explanation:

x ≤ -7 and x ≥ -2

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PLEASE HELP!!!!!!! I NEED HELP!!!!!!!!!!
miss Akunina [59]

Answer:

342in

Step-by-step explanation:

7 0
3 years ago
Consider the following theorem. Theorem If f is integrable on [a, b], then b a f(x) dx = lim n→[infinity] n i = 1 f(xi)Δx where
mel-nik [20]

Split up the interval [1, 9] into <em>n</em> subintervals of equal length (9 - 1)/<em>n</em> = 8/<em>n</em> :

[1, 1 + 8/<em>n</em>], [1 + 8/<em>n</em>, 1 + 16/<em>n</em>], [1 + 16/<em>n</em>, 1 + 24/<em>n</em>], …, [1 + 8 (<em>n</em> - 1)/<em>n</em>, 9]

It should be clear that the left endpoint of each subinterval make up an arithmetic sequence, so that the <em>i</em>-th subinterval has left endpoint

1 + 8/<em>n</em> (<em>i</em> - 1)

Then we approximate the definite integral by the sum of the areas of <em>n</em> rectangles with length 8/<em>n</em> and height f(x_i) :

\displaystyle \int_1^9 (x^2-4x+6) \,\mathrm dx \approx \sum_{i=1}^n \frac8n\left(\left(1+\frac8n(i-1)\right)^2-4\left(1+\frac8n(i-1)\right)+6\right)

Take the limit as <em>n</em> approaches infinity and the approximation becomes exact. So we have

\displaystyle \int_1^9 (x^2-4x+6) \,\mathrm dx = \lim_{n\to\infty} \sum_{i=1}^n \frac8n\left(\left(1+\frac8n(i-1)\right)^2-4\left(1+\frac8n(i-1)\right)+6\right) \\\\ = \lim_{n\to\infty} \frac8n \sum_{i=1}^n \left(1+\frac{16}n(i-1)+\frac{64}{n^2}(i-1)^2-4-\frac{32}n(i-1)+6\right) \\\\= \lim_{n\to\infty} \frac8{n^3} \sum_{i=1}^n \left(64(i-1)^2-16n(i-1)+3n^2\right) \\\\= \lim_{n\to\infty} \frac8{n^3} \sum_{i=0}^{n-1} \left(64i^2-16ni+3n^2\right) \\\\= \lim_{n\to\infty} \frac8{n^3} \left(64\sum_{i=0}^{n-1}i^2 - 16n\sum_{i=0}^{n-1}i + 3n^2\sum{i=0}^{n-1}1\right) \\\\= \lim_{n\to\infty} \frac8{n^3} \left(\frac{64(2n-1)n(n-1)}{6} - \frac{16n^2(n-1)}{2} + 3n^3\right) \\\\= \lim_{n\to\infty} \frac8{n^3} \left(\frac{49n^3}3-24n^2+\frac{32n}3\right) \\\\= \lim_{n\to\infty} \frac{8\left(49n^2-72n+32\right)}{3n^2} = \boxed{\frac{392}3}

3 0
3 years ago
3a2 + 2a + 2a2 is equal to​
yanalaym [24]

Answer:

  5a^2 +2a

Step-by-step explanation:

Like terms are ones with the same exponent of x. They can be combined.

  3a^2 +2a +2a^2

  = (3a^2 +2a^2) +2a

  = (3+2)a^2 +2a

  = 5a^2 +2a

4 0
2 years ago
Read 2 more answers
Experiments on learning in animals sometimes measure how long it takes mice to find their way through a maze. The mean time is 1
Nuetrik [128]

Answer:

attached

Step-by-step explanation:

attached

Download docx
8 0
3 years ago
What is the value of x in the equation 4(2x + 10) = 0? (1 point)
miskamm [114]

Answer:

x = -5

Explanation:

4(2x + 10) = 0

[ Simplify both sides of the equation ]

4(2x + 10) = 0

(4)(2x) + (4)(10) = 0 [Distribute]

8x + 40 = 0

[ Subtract 40 from both sides ]

8x + 40 − 40 = 0 − 40

8x = −40

[ Divide both sides by 8 ]

8x  / 8 = −40 / 8

x = -5

4 0
2 years ago
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