Answer:
7n-20 I believe
Step-by-step explanation:
hope this helps
It will be 42 because of the with times the 2nd highest
No because 7/9= 0.777777777789 and 8/9= 0.888888888888889
Answer: 0.038
Step-by-step explanation:
Given: Total games : n= 375
Number of games won by the team that was winning the game at the end of the third quarter. = 300
The proportion (p) of the team that was winning the game at the end of the third quarter: 
Critical z-value for 90% confidence: z* = 1.645
Margin of error =
The margin of error in a 90% confidence interval estimate of p 
Hence, the required margin of error = 0.038