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3 years ago

Substitution method x=3y-8

1 answer:

4 0

Explanation:
Solving the first equation for
x
:
x
=
8
−
3
y

Substituting this ( for
x
)in the second equation
2
(
8
−
3
y
)
−
y
=
9
expanding
16
−
6
y
−
y
=
9
16
−
7
y
=
9

so
7
y
=
7
so
y
=
1
and
x
=
8
−
3
x
=
5

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Answer plz it’s a easy I think I don’t know

Paha777 [63]

Answer:

√2 < 1.8

Step-by-step explanation:

Square of 2 is 1.41421356237309 and that is less than 1.8 continued.

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4 years ago

Write 4 4/5 as an improper fraction

Rasek [7]

Step-by-step explanation:

4⅘=22/5.

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3 years ago

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Graph the function f(x)=4x^2+ 3x - 1

Marizza181 [45]

Step-by-step explanation:

The graph of a quadratic function is a U-shaped curve called a parabola. One important feature of the graph is that it has an extreme point, called the vertex. If the parabola opens up, the vertex represents the lowest point on the graph, or the minimum value of the quadratic function. If the parabola opens down, the vertex represents the highest point on the graph, or the maximum value. In either case, the vertex is a turning point on the graph. The graph is also symmetric with a vertical line drawn through the vertex, called the axis of symmetry.

Graph of a parabola showing where the x and y intercepts, vertex, and axis of symmetry are.

The

-intercept is the point at which the parabola crosses the

-axis. The

-intercepts are the points at which the parabola crosses the

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at which

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3 years ago

- Polynomial Functions -For each function, state the vertex; whether the vertex is a maximum or minimum point; the equation of t

vladimir2022 [97]

EXPLANATION

Given the function f(x) = (x-6)^2 + 1

$\mathrm{The\: vertex\: of\: an\: up-down\: facing\: parabola\: of\: the\: form}\: y=ax^2+bx+c\: \mathrm{is}\: x_v=-\frac{b}{2a}$

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

$=x^2-12x+37$ $\mathrm{The\: parabola\: params\: are\colon}$ $a=1,\: b=-12,\: c=37$ $x_v=-\frac{b}{2a}$ $x_v=-\frac{\left(-12\right)}{2\cdot\:1}$ $\mathrm{Simplify}$ $x_v=6$ $y_v=6^2-12\cdot\: 6+37$

Simplify:

$y_v=1$

$\mathrm{Therefore\: the\: parabola\: vertex\: is}$ $\mleft(6,\: 1\mright)$ $\mathrm{If}\: a$ $\mathrm{If}\: a>0,\: \mathrm{then\: the\: vertex\: is\: a\: minimum\: value}$ $a=1$ $\mathrm{Minimum}\mleft(6,\: 1\mright)$ $\mathrm{For\: a\: parabola\: in\: standard\: form}\: y=ax^2+bx+c\: \mathrm{the\: axis\: of\: symmetry\: is\: the\: vertical\: line\: that\: goes\: through\: the\: vertex}\: x=\frac{-b}{2a}$

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

$y=x^2-12x+37$ $\mathrm{Axis\: of\: Symmetry\: for}\: y=ax^2+bx+c\: \mathrm{is}\: x=\frac{-b}{2a}$ $a=1,\: b=-12$ $x=\frac{-\left(-12\right)}{2\cdot\:1}$ $\mathrm{Refine}$

Axis of simmetry : x=6

The quadratic function has the same shape than the parent function y=x^2 because there is NOT a coefficient within x.

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1 year ago

Write the following equation in general form 4x-6y=14

Maru [420]

A. 4x-6y-14 = 0

Math & Reasoning:

You cannot simplify 4x-6y=14 any other way than subtracting 14 from both sides. You could solve for X and Y, but it'd be a long process and by the time you did that you would have it in it's most simplified form.

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4 years ago