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3 years ago

Help me I want a perfect grade

Mathematics

1 answer:

Zolol [24]3 years ago

3 0

Answer:

2x+10

x=55

Step-by-step explanation:

Perimeter = 2(5+x) = 2x+10

SECOND QUESTION

2x+10=120

2x=110

x=55

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Sphere A has a radius of 24 centimeters, and sphere B has a diameter of 42 centimeters. The radius of sphere A is multiplied by

Tamiku [17]

Answer:

7/8

Step-by-step explanation:

Sphere A has a radius of 24 centimeters, and sphere B has a diameter of 42 centimeters.

WE need find which factor is multiplied with radius of sphere A to produce the radius of sphere B

Diameter of sphere B is 42

Radius = diameter /2

Radius = 42/2= 21

Radius of sphere B = 21

RAdius of sphere A times x= radius of sphere B

24 * x= 21

Divide by 24 on both sides

x= 21/ 24

divide top and bottom by 3

x= 7/ 8

5 0

3 years ago

Read 2 more answers

ASAP WHO EVER ANSWER THESE WILL BE MARKED BRANLIEST

valentinak56 [21]

Answer:

i dont know honestly

Step-by-step explanation:

3 0

3 years ago

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )

Gemiola [76]

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:$ or $x-4\:>\:8$

$x\:$ or $x\:>\:8+4$

$x\:$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -\frac{10}{3}$ and $x\leq 2$

$-\frac{10}{3}\leq x\leq2$

We write this in interval form to get,

$[-\frac{10}{3},2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:$ or $1-5a\:>\:29$

This implies that,

$-5a\:$ or $-5a\:>\:29-1$

$-5a\:$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:$

We write this in interval notation to get,

$(-\infty,-\frac{28}{5})\cup (6,+\infty)$

7 0

3 years ago

Sam needs a web designer. Designer A is offering her services for an initial $510 in addition to $80 per hour. Designer B is off

lutik1710 [3]

Answer:

The answer is when they work 4 hours x=4

Step-by-step explanation:

510 + 80x = 650 + 45x

80x - 45x = 650 - 510

35x = 140

x = 140/35

x = 4 hours

3 0

4 years ago

Could you please look at this question?

MrMuchimi

Answer:

a. see attached

b. H(t) = 12 -10cos(πt/10)

c. H(16) ≈ 8.91 m

Step-by-step explanation:

The cosine function has its extreme (positive) value when its argument is 0, so we like to use that function for circular motion problems that have an extreme value at t=0. The midline of the function needs to be adjusted upward from 0 to a value that is 2 m more than the 10 m radius. The amplitude of the function will be the 10 m radius. The period of the function is 20 seconds, so the cosine function will be scaled so that one full period is completed at t=20. That is, the argument of the cosine will be 2π(t/20) = πt/10.

The function describing the height will be ...

H(t) = 12 -10cos(πt/10)

The graph of it is attached.

See part a.

The wheel will reach the top of its travel after 1/2 of its period, or t=10. Then 6 seconds later is t=16.

H(16) = 12 -10cos(π(16/10) = 12 -10cos(1.6π) ≈ 12 -10(0.309017) ≈ 8.90983

The height of the rider 6 seconds after passing the top will be about 8.91 m.

8 0

3 years ago