Answer:
you can use reciprocal and quotient formula of trigonometry
Answer:
624.102
Step-by-step explanation:
pls give brainliest im new and need points
Answer:
whats the problem? ill do my best to help
Step-by-step explanation:
Hope this helps! Plz give brainliest! Also, plz sub to Kgirl633 on yt.
Answer and explanation:
Keira could get or look up an electronic copy of the book online. Once she has an electronic copy(pdf for instance) of the book, she can count number of e's in her book using the PDF reader or any software extension(good number of tools online) that would do just that.
Factors for Keira to consider:
How many lines and words are there on average per page; how many words are there per line?
How many e's are there manually counting for at least 5 pages.
Problems Keira might have in collecting data:
If book is physical and not an electronic copy, Keira may have to go through a tedious task of counting manually. She could make a rough estimation based on a few pages counted but she would need more accurate figures which requires the tedious task of counting e 's manually
Answer:
For the first case converting ml to L we got:
And we see that 0.2 L is lower than 2 L so then:
And in the other way if we convert L to mL we got:
And we see that [/tex] 200mL < 2000 mL[/tex]
So then the answer would be <
Step-by-step explanation:
For this case we can solve this problem converting ml to L or converting L to ml.
For the first case converting ml to L we got:
And we see that 0.2 L is lower than 2 L so then:
And in the other way if we convert L to mL we got:
And we see that [/tex] 200mL < 2000 mL[/tex]
So then the answer would be <
