Answer:
Step-by-step explanation:
hello :
2x² + 25 = -x² + 10x
2x²+x²-10x+25 =0
3x²-10x+25=0
∆ = b²- 4ac a=3 and b=-10 and c=25
∆ = (-10)²- 4(3)(25)=100 -300 = -200< 0
two complex solutions
Answer:
-14
Step-by-step explanation:
(-5)+(-2)-8-(-1)
-5-2-8+1
-7-8+1
-15+1
-14
(x + 2y)^10
(x + 2y)(x + 2y)(x + 2y)(x + 2y)(x + 2y)(x + 2y)(x + 2y)(x + 2y)(x + 2y)(x + 2y)
(x² + 4xy + 4y)(x² + 4xy + 4y)(x² + 4xy + 4y)(x² + 4xy + 4y)(x² + 4xy + 4y) (x^4+8x³y+8x²y+16x²y²+20xy²+16y²)(x^4+8x³y+8x²y+16x²y²+20xy²+16y²)(x²+4xy+4y)
Answer:
(4x - 5)(x + 2).
Step-by-step explanation:
4x^2 + 3x - 10
4 * 10 = -40
We need 2 numbers whose product is -40 and whose sum is +3.
Theses are = - 5 and + 8.
So we write:
4x^2 + 8x + -5x - 10
= 4x(x + 2) - 5(x + 2)
= (4x - 5)(x + 2).
Answer:
c because its c its c and nothing but c