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3 years ago

Please help on number 23!!!

Mathematics

2 answers:

Rainbow [258]3 years ago

6 0

Show us the polygon___

Oksanka [162]3 years ago

4 0

Answer:

he is incorrect the biggest angle u could have is probably a 359 which probably looks like a circle it just ain't possible.

Step-by-step explanation:

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Which of the following is equal to 2 2/5 <br>A. 1 7/5 <br>B. 1 12/5 <br>C. 1 6/5 <br>D. 1 9/5

Viefleur [7K]

I think it is B I am guessing

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3 years ago

Read 2 more answers

If two numbers on a fraction are negative, does that make the fraction positive

Sedbober [7]

I think the answer is yes

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3 years ago

How many centimeters in 3.7 kilometers?

lana66690 [7]

Answer:

370,000 centimeters

Step-by-step explanation:

1. There are 1000 meters in a kilometer.

2. 3.7 kilometers x 1000 = 3,700 meters

3. There are 100 centimeters in a meter

4. 3,700 x 100 = 370,000 centimeters

5 0

2 years ago

Sasha finished mowing lawns at 4:15 PM. It took 1 3/4h to mow the first lawn. The second and third lawns she mowed each took 1 1

ddd [48]

The time it took to mow all the lawns including the break he took was 1 3/4+1 1/5+1 1/5+3/4=
2 1/2+2 2/5= 4 9/10 which is 4 hours and 54 minutes and if he got done at 4:15pm then he started 4 hours and 54 minutes before at
C. 11:21 A.M.

6 0

3 years ago

Clark and Lana take a 30-year home mortgage of $128,000 at 7.8%, compounded monthly. They make their regular monthly payments fo

svp [43]

Answer:

Step-by-step explanation:

From the given information:

The present value of the house = 128000

interest rate compounded monthly r = 7.8% = 0.078

number of months in a year n= 12

duration of time t = 30 years

To find their regular monthly payment, we have:

$PV = P \begin {bmatrix} \dfrac{1 - (1 + \dfrac{r}{n})^{-nt}}{\dfrac{r}{n}} \end {bmatrix}$

$128000 = P \begin {bmatrix} \dfrac{1 - (1 + \dfrac{0.078}{12})^{- 12*30}}{\dfrac{0.078}{12}} \end {bmatrix}$

128000 = 138.914 P

P = 128000/138.914

P = $921.433

∴ Their regular monthly payment P = $921.433

To find the unpaid balance when they begin paying the $1400.

when they begin the payment ,

t = 30 year - 5years

t= 25 years

$PV= 921.433 \begin {bmatrix} \dfrac{1 - (1 - \dfrac{0.078}{12})^{25*30}}{\dfrac{0.078}{12}} \end {bmatrix}$

PV = $121718.2714

C) In order to estimate how many payments of $1400 it will take to pay off the loan, we have:

$121718.2714 = \begin {bmatrix} \dfrac{1300 (1 - \dfrac{12.078}{12}))^{-nt}}{\dfrac{0.078}{12}} \end {bmatrix}$

$121718.2714 = 200000 \begin {bmatrix} (1 - \dfrac{12.078}{12}))^{-nt} \end {bmatrix}$

$\dfrac{121718.2714}{200000 } = \begin {bmatrix} (1 - \dfrac{12.078}{12}))^{-nt} \end {bmatrix}$

$0.60859 = \begin {bmatrix} (1 - \dfrac{12}{12.078}))^{nt} \end {bmatrix}$

$0.60859 = (0.006458)^{nt}$

$nt = \dfrac{0.60859}{0.006458}$

nt = 94.238 payments is required to pay off the loan.

How much interest will they save by paying the loan using the number of payments from part (c)?

The total amount of interest payed on $921.433 = 921.433 × 30(12) years

= 331715.88

The total amount paid using 921.433 and 1300 = (921.433 × 60 )+( 1300 + 94.238)

= 177795.38

The amount of interest saved = 331715.88 - 177795.38

The amount of interest saved = $153920.5

6 0

4 years ago