This is the only way I can think of this mathematically. This took a good 20 minutes for me. You need to guess and check. Like try 17 quarters, 50 nickels, and 37 dimes etc. until you get 11.00. My numbers are mathematically correct but we both know you cant have 18.909 quarters so. lol
Answer:
Quarters: 18.909
Nickels: 49.818
Dimes: 37.818
Somewhere around those numbers.
Step-by-step explanation:
$11.00 total in coins
Nickel = $0.05
Dime = $0.10
Quarter = $0.25
(n*0.05) + (d*0.10) + (q*0.25)
Solve the equation for q.
(n*0.05) + (d*0.10) +( 
*0.25)
Simplify the expression.
9d + 2n = 440
d - n = -12
Multiply both sides of the equation by -9.
-9d + 9n = 108
9d + 2n = 440
Sum the equations vertically to eliminate at least one variable.
11n = 548
Substitute the given value of n into the equation d - n = -12
Substitute the given value of n into the equation
Finally
d = 37.818
n = 49.818
q = 18.909
The horizontal distance is given by the formula:
tan θ=opposite/adjacent
where:
θ=21
opposite=2000 ft
adjacent=a
thus calculating for a we get:
tan 21=2000/a
thus
a=2000/tan 21
a=5210.18 ft
Answer: 5210.18 ft
Answer:
System of linear equations
a: adult ticket price and c: child ticket price
Step-by-step explanation:
This system of equations can be used to find the price of the adult and child tickets.
We have two equations (one for each day) and two unknowns (adult ticket price and child ticket price).
Let a: adult ticket price and c: child ticket price,
we have for the first day that 3 adult tickets and 1 child ticket adds $38:
and for the second day we have that 2 adult tickets and 2 child tickets adds $52:
If we write this as a system of equations, we have:
Answer:
cdfJNMUCDJUNMCDJUUJNUJNHMKVSDFJNUMLSKLHUKJNHMC V
Step-by-step explanation:
hope that help
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