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Step2247 [10]
3 years ago
10

Given the following formula solve for y.​

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
4 0

Answer:

D.  y = x-2(w+z)  

Step-by-step explanation:

w = (x-y)/2 -z

Add z to each side

w+z = (x-y)/2 -z +z

w+z = (x-y)/2

Multiply each side by 2

2(w+z) = (x-y)/2  *2

2(w+z) = x-y

Subtract x from each side

2(w+z) -x = x-y-x

2(w+z) -x = -y

Multiply each side by -1

-2(w+z) +x = y

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A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2: S
Anna35 [415]

Answer:

The 98% confidence interval for the population proportion of disks which are defective is (0.082, 0.118).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Suppose a sample of 1536 floppy disks is drawn. Of these disks, 1383 were not defective.

1536 - 1383 = 153

This means that n = 1536, \pi = \frac{153}{1536} = 0.1

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1 - 2.327\sqrt{\frac{0.1*0.9}{1536}} = 0.082

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1 + 2.327\sqrt{\frac{0.1*0.9}{1536}} = 0.118

The 98% confidence interval for the population proportion of disks which are defective is (0.082, 0.118).

6 0
3 years ago
Pls help if u know math
Minchanka [31]

Answer:

x = 4

y = 11

Step-by-step explanation:

Set  your formula as follow:

2x+3=3x-1 -> 2x+3-3x=-1  -> -x+3 = -1 -> -x=-4 -> x=4

now substitute x for 4 in the following

y-2=2(4)+1 -> y-2=8+1 ->y-2 = 9y -> y=11

6 0
3 years ago
Read 2 more answers
Find two consecutive integers whose sum is -13
Lemur [1.5K]

Answer:

-6 and -7

Step-by-step explanation:

Set up an equation: x+x+1=-13 2x=-14 x=-7. Since it is negative, you go down 1. -6 and -7 hope this helps plz mark brainliest if correct

4 0
3 years ago
Plot the points A(9, 11) and B(–3, –5). Find midpoint M of AB. Then show that AM = MB and AM + MB =AB
Alex_Xolod [135]

Answer:

The midpoint is (3, 3).

Step-by-step explanation:

We are given the two points A(9, 11) and B(-3, -5).

The midpoint is given by:

\displaystyle M=\Big(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\Big)

So:

\displaystyle M =  \Big( \frac{9+(-3) }{2}, \frac{ 11+(-5) }{2} \Big) = (3,3)

The midpoint is (3, 3).

We want to show that AM = MB.

We can use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

The distance between A(9, 11) and M(3, 3) will then be:

AM=\sqrt{(9-3)^2+(11-3)^2}=\sqrt{6^2+8^2}=\sqrt{100}=10

And the distance between B(-3, -5) and M(3, 3) will be:

MB = \sqrt{ (3-(-3))^2 + (3-(-5))^2 } = \sqrt{(6)^2+(8)^2} = \sqrt{ 100 } = 10

So, AM = MB = 10.

Since AM = MB = 10, AM + MB = 10 + 10 = 20.

So, we want to prove that AB = 20.

By the distance formula:

AB=\sqrt{(9-(-3))^2+(11-(-5))^2}=\sqrt{12^2+16^2}}=\sqrt{400}=20\stackrel{\checkmark}{=}20

4 0
3 years ago
The isotope known as carbon-14 is radioactive and will decay into the stable form nitrogen-14. As long as an organism is alive,
yan [13]

Answer:

The number of half lives in 14000 years is  2.4258.

Step-by-step explanation:

Initial amount of carbon-14 =N_o

Final amount of carbon-14= N

Half life of carbon-14 = t_{1/2}=5770 year

Decay constant = k = \frac{0.693}{t_{1/2}}=\frac{0.693}{5770 year}

Age of the sample = t = 14,000 years

N=N_o\times e^{-kt}

N=N_o\times e^{-\frac{0.693}{5770 year}\times 14,000 yeras}

N=N_o\times 0.1861

Formula used for number of half lives

N=\frac{N_o}{2^n}

where,

N= amount of reactant left after n-half lives

N_o = Initial amount of the reactant

n = number of half lives

N_o\times 0.1861=\frac{N_o}{2^n}

2^n=\frac{1}{0.1861}

2^n=5.3734

Taking log both sides

n\log 2=\log (5.3734)

n = 2.4258

The number of half lives in 14000 years is  2.4258.

7 0
3 years ago
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