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nadezda [96]
3 years ago
9

Help please i dont know how to do this

Mathematics
2 answers:
Fantom [35]3 years ago
5 0

Answer:

make a graph

onlyyyyyy

Step-by-step explanation:

hope it's helpful for u

Dmitry_Shevchenko [17]3 years ago
4 0

Step-by-step explanation:

MLCs are chosen in the following manner: One third are elected by the members of local bodies such as municipalities, Gram panchayats, Panchayat samitis and district councils

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Is there any combination of education and post-graduation? Write the five basic objectives of education
Degger [83]

Answer:

3

Step-by-step explanation:

Actually 'post-graduation' is a type of education. Education only means learning, so post graduation is a type of education.

<u>OBJECTIVES OF EDUCATION:</u>

Usually an educational objective relates to gaining an ability, a skill, some knowledge, a new attitude etc. rather than having merely completed a given task.

5 0
4 years ago
Read 2 more answers
Please helppppp pls it's in the screenshot
sergey [27]

Answer:

  4. 11/6, 121/36

  5. 5/8, 25/64

  6. 4/7, 16/49

  7. 14/9, 196/81

Step-by-step explanation:

The ratio of perimeters is the same as the ratio of corresponding legs:

  perimeter ratio = red leg/blue leg

The area ratio is the square of that:

  area ratio = (perimeter ratio)²

__

<h3>4.</h3>

perimeter ratio = 11/6

area ratio = (11/6)² = 121/36

__

<h3>5.</h3>

perimeter ratio = 5/8

area ratio = (5/8)² = 25/64

__

<h3>6.</h3>

perimeter ratio = 4/7

area ratio = (4/7)² = 16/49

__

<h3>7.</h3>

perimeter ratio = 14/9

area ratio = (14/9)² = 196/81

3 0
2 years ago
<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7
Katen [24]

\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

4 0
3 years ago
24+82 rounding or compatible numbers to estimate the sum
allsm [11]

Answer:

106

Step-by-step explanation:

you take 82 and 24 and add them together so it would be like this 2 + 4 = 6 and 8 + 2 = 10 so the 8 is in a tens place so the answer from adding 8 + 2 = 100 because you in the tens place so the final answer would be 106 after adding it all up.

4 0
2 years ago
(x – 10) + (3x – 6) =<br> please someone help?
lyudmila [28]

Answer:

4x-4

Step-by-step explanation:

x-10+3x+6=4x-4

Hope helps :3

7 0
3 years ago
Read 2 more answers
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