The trick to this question is the find the least common multiple of 20 and 15. You could do 20×3=60 and 15×4=60 as those both equal the same number yet you there are no other multiples they share before 60. So the next time the two schools will eat pizza on the same day again will be in 60 days. Hope this helps!
Answer:
this is the anwser
Step-by-step explanation:
4 12 13 triangle
Obtuse scalene triangle.
Sides: a = 4 b = 12 c = 13
Area: T = 23.894
Perimeter: p = 29
Semiperimeter: s = 14.5
Angle ∠ A = α = 17.839° = 17°50'19″ = 0.311 rad
Angle ∠ B = β = 66.782° = 66°46'55″ = 1.166 rad
Angle ∠ C = γ = 95.379° = 95°22'46″ = 1.665 rad
Height: ha = 11.947
Height: hb = 3.982
Height: hc = 3.676
Median: ma = 12.349
Median: mb = 7.517
Median: mc = 6.144
Inradius: r = 1.648
Circumradius: R = 6.529
Vertex coordinates: A[13; 0] B[0; 0] C[1.577; 3.676]
Centroid: CG[4.859; 1.225]
Coordinates of the circumscribed circle: U[6.5; -0.612]
Coordinates of the inscribed circle: I[2.5; 1.648]
Exterior (or external, outer) angles of the triangle:
∠ A' = α' = 162.161° = 162°9'41″ = 0.311 rad
∠ B' = β' = 113.218° = 113°13'5″ = 1.166 rad
OK so we know that the other side is 12 because the right triangle has to have two sides that add up to the hypotenuse, and I believe it gives you the answer in the question because you are trying to find x which it says x is the angle, and since its a right triangle, it would be 90°
A= 4 tenth 2 hundredth 3 thousandth
b= 3 tenth 2 hundredth 6 thousandth 7 ten thousandth 8 hundred thousandth
c= 4 tenth 5 hundredth 2 thousandth 4 ten thousandth
d= 3 tenth 0 hundredth 0 thousandth 6 ten thousandth
Question 1: Equiangular
Question 2: Area of the parallelogram = 48 square centimeters
Question 3: Perimeter of the rectangle = 42 ft
Question 4: Area of the trapezoid = 154 square inches
Solution:
Question 1:
The given polygon is a rectangle.
The angles of each side of the polygon is 90°.
This means all angles are equal.
Hence Option A equiangular is the correct answer.
Question 2:
Area of the parallelogram = Base × Height]
= 6 cm × 8 cm
Area of the parallelogram = 48 square centimeters
Question 3:
Perimeter of the rectangle = 2(length + width)
= 2( 15 ft + 6 ft)
= 2(21 ft)
Perimeter of the rectangle = 42 ft
Question 4:
Area of the trapezoid = 
Area of the trapezoid = 154 square inches
